At one end of a production line, Isaac puts peaches into cans on a conveyor belt. He fills 18 cans per minute. As soon as Isaac
has filled 670 cans on the conveyor belt, Albert starts putting lids on the cans at the other end of the production line. As Albert finishes closing each can, he moves up along side the conveyor belt to meet the next can. Albert puts lids on 50 cans per minute. (Assume that the conveyor belt initially had no cans on it, and that Isaac stays in place as he continues to fill cans.) How long does it take for Albert to reach Isaac (measured from when Albert starts putting on lids)?
1 answer:
Answer: Long answer...
<em>Explanation:</em> As soon as Isaac has filled 670 cans on the conveyor belt, Albert starts putting lids on the cans at the other end of the production line. As Albert finishes closing each can, he moves up along side the conveyor belt to meet the next can. Albert puts lids on 50 cans per minute.
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Answer:
a)
b)
Explanation:
Given:
- upward acceleration of the helicopter,
- time after the takeoff after which the engine is shut off,
a)
<u>Maximum height reached by the helicopter:</u>
using the equation of motion,
where:
u = initial velocity of the helicopter = 0 (took-off from ground)
t = time of observation
b)
- time after which Austin Powers deploys parachute(time of free fall),
- acceleration after deploying the parachute,
<u>height fallen freely by Austin:</u>
where:
initial velocity of fall at the top = 0 (begins from the max height where the system is momentarily at rest)
time of free fall
<u>Velocity just before opening the parachute:</u>
<u>Time taken by the helicopter to fall:</u>
where:
initial velocity of the helicopter just before it begins falling freely = 0
time taken by the helicopter to fall on ground
height from where it falls = 250 m
now,
From the above time 7 seconds are taken for free fall and the remaining time to fall with parachute.
<u>remaining time,</u>
<u>Now the height fallen in the remaining time using parachute:</u>
<u>Now the height of Austin above the ground when the helicopter crashed on the ground:</u>
Assuming the accleration applied was constant, we have
Then the force applied to the ball is given by