A 0.40-kg block is attached to the end of a horizontal ideal spring and rests on a frictionless surface. The block is pulled so
1 answer:
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Answer:
T= 38.38 N
Explanation:
Here
mass of can = m = 3 kg
g= 9.8 m/sec2
angle θ = 40°
From figure we see the vertical and horizontal component of tension force T
If the can is to slip - then horizontal component of tension force should become equal to force of friction.
First we find force of friction
Fs= μ R
where
μ = 0.76
R = weight of can = mg = 3 × 9.8 = 29.4 N
Now horizontal component of tension
Tx= T cos 40 = T× 0.7660 N
==>T× 0.7660 = 29.4
==> T= 38.38 N
Answer:
Explanation:
Height of the cliff is given as
now the time taken by the diver to hit the surface is given as
Now in the same time it has to cover a distance of 13.39 m
so the speed in horizontal direction is given as
Answer:
(a). The speed of electron is .
(b). The radius of electron is
Explanation:
Given that,
Length = 2.5 cm
Distance = 6.0 mm
Magnetic field = 2.1 T
Potential difference = 700 V
(a). We need to calculate the electron's speed
Using formula of speed
Put the value into the formula
(b). We need to calculate the radius of electron
Using formula of centripetal force
Where,
m = mass of electron
v = speed of electron
r = radius
q = charge of electron
B = magnetic field
Put the value into the formula
Hence, (a). The speed of electron is .
(b). The radius of electron is 4.2 cm