Name the following polyatomic ionic compound: (NH4)2S.

pshichka [43]

Answer:

Nanotechnology is the term given to those areas of science and engineering where phenomena that take place at dimensions in the nanometre scale are utilised in the design, characterisation, production and application of materials, structures, devices and systems.

6 0

3 years ago

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Two planets P1 and P2 orbit around a star S in circular orbits with speeds v1 = 40.2 km/s, and v2 = 56.0 km/s respectively. If t

Readme [11.4K]

Answer: $3.66(10)^{33}kg$

Explanation:

We are told both planets describe a circular orbit around the star S. So, let's approach this problem begining with the angular velocity $\omega$ of the planet P1 with a period $T=750years=2.36(10)^{10}s$ :

$\omega=\frac{2\pi}{T}=\frac{V_{1}}{R}$ (1)

Where:

$V_{1}=40.2km/s=40200m/s$ is the velocity of planet P1

$R$ is the radius of the orbit of planet P1

Finding $R$ :

$R=\frac{V_{1}}{2\pi}T$ (2)

$R=\frac{40200m/s}{2\pi}2.36(10)^{10}s$ (3)

$R=1.5132(10)^{14}m$ (4)

On the other hand, we know the gravitational force $F$ between the star S with mass $M$ and the planet P1 with mass $m$ is:

$F=G\frac{Mm}{R^{2}}$ (5)

Where $G$ is the Gravitational Constant and its value is $6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$

In addition, the centripetal force $F_{c}$ exerted on the planet is:

$F_{c}=\frac{m{V_{1}}^{2}}{R^{2}}$ (6)

Assuming this system is in equilibrium:

$F=F_{c}$ (7)

Substituting (5) and (6) in (7):

$G\frac{Mm}{R^{2}}=\frac{m{V_{1}}^{2}}{R^{2}}$ (8)

Finding $M$ :

$M=\frac{V^{2}R}{G}$ (9)

$M=\frac{(40200m/s)^{2}(1.5132(10)^{14}m)}{6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}}$ (10)

Finally:

$M=3.66(10)^{33}kg$ (11) This is the mass of the star S

4 0

4 years ago

HEY CAN ANYONE PLS ANSWER DIS!!!!!!

snow_lady [41]

Answer:

Explanation:

1.wrap bar magnet in a plastic baggie and remove the iron filings from the mixture by using a bar magnet. Place a small piece of scrap paper on the scale and “tare” the scale. Then place filings on the scrap paper and record (e) the mass of the iron filings. Don't throw out the iron–save it to be recollected.

2.When sand is added to water it either hangs in the water or forms a layer at the bottom of the container. Sand therefore does not dissolve in water and is insoluble. It is easy to separate sand and water by filtering the mixture. Salt can be separated from a solution through evaporation.

3.Sand (mostly silicon dioxide) is not.

Pour the salt and sand mixture into a pan.

Add water. ...

Heat the water until the salt dissolves. ...

Remove the pan from heat and allow it to cool until it's safe to handle.

Pour the salt water into a separate container.

Now collect the sand.

Pour the salt water back into the empty pan.

Heat the salt water until the water boils. Continue boiling it until the water is gone and you're left with the salt.

Another way you can separate the salt water and sand is to stir up the sand/salt water and pour it through a coffee filter to capture the sand.

8 0

4 years ago

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Monochromatic light with wavelength 590 nm passes through a single slit 2. 30 ?m wide and 1. 90 m from a screen. Find the distan

aivan3 [116]

Answer:

The fringes are 4.7*10^-7 m apart, such that they are adjacent.

Explanation:

Using the formula for adjacent fringes given a single slit:

Δ $x=\frac{(Wavelength)(Distance between slit and screen)}{Width}$

Δ $x=\frac{(590/10^{9})(1.90) }{(2.30)}$

Δ $x=0.000000487 m$

Hope this helps!

7 0

2 years ago

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If an individual exercised by riding a bike with a friend for 30 minutes on a flat trail and they were engaged in a conversation

Anna35 [415]

Answer:

Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??

Explanation:

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fhwjwli ljyw uluyfw Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??Those who don't have doubt can they leave ??

7 0

3 years ago