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andre [41]
3 years ago
6

PLEASE HELP!! Algebra 2 Review !!

Mathematics
1 answer:
Kamila [148]3 years ago
6 0

Answer:

\frac{28-3i}{26}

Step-by-step explanation:

For #2, remember that i=\sqrt{-1}, so i^{2}=-1 Also, (a+b)(a-b), where a and b are any numbers, (a+b)(a-b)=a^2-b^2. Now, to simplify, or radicalize, a number with surds in the denominator, you have to multiply the denominator by its conjugate. If there is a complex number a+bi, where a and b are any numbers, the conjugate is always a-bi. Lets apply these rules. The conjugate of 4+6i is 4-6i, so do this:

\frac{5+6i}{4+6i}=\frac{(5+6i)(4-6i)}{(4+6i)(4-6i)}=\frac{20+24i-30i+36}{16+36}=\frac{56-6i}{52}=\frac{2(28-3i)}{2(26)}=\frac{28-3i}{26}

Our answer is (28-3i)/(26)!

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The answer is 72.1.you should dot infront sizes and then equals them
6 0
3 years ago
A recipe calls for 1 ½ cups of flour, 2/3 cup of white sugar, and 1/3 cup of brown sugar. The recipe makes 6 servings. A) How ma
Goryan [66]
<span>A) How many cups of flour are there per serving? 

</span>1 ½ cups of flour --------<span>6 servings
?     cups of flour ------- 1 serving

      </span>1 ½ 
------------ 
        6 

= 3/2 x 1/6
= 1/4

answer: 1/4 cups of flour per serving

<span>B) how many total cups of sugar(white and brown) are there per serving?
</span>total white and brown: <span>2/3 + 1/3 = 3/3 = 1 cups (combine)

1 cup of sugar (white and brown) </span>--------6 servings
? cups of sugar (white and brown) ------ 1 serving

  1
-----  = 1/6
  6
answer: 1/6 cups of sugar (white and brown) per serving

<span> (c) Suppose you modify the recipe so that it makes 9 servings. How much more flour do you need for the modified recipe than you need for the original recipe?
</span>
3/2  cups of flour --------6 servings
? cups of flour -----------9 servings


  9 * 3/2             
-----------  
      6

= (13 1/2) / 6
= 2 1/4

2 1/4 ( 9 servings) - 1 1/2(6 servings) = 3/4 cups

answer: you need 3/4 more cups of flour

6 0
3 years ago
Read 2 more answers
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melamori03 [73]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Suppose that the sitting​ back-to-knee length for a group of adults has a normal distribution with a mean of mu equals 24.4 in.
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Answer:

P(X \geq 26.6) = 0.0336, which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 24.4, \sigma = 1.2

In this problem, a value x is significantly high if:

P(X \geq x) = 0.01

Using these​ criteria, is a​ back-to-knee length of 26.6 in. significantly​ high?

We have to find the probability of the length being 26.6 in or more, which is 1 subtracted by the pvalue of Z when X = 26.6. So

Z = \frac{X - \mu}{\sigma}

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6 0
3 years ago
Add or subtract. Write the result in the form a+bi
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Number 2: (3-3i)-(4+7i)

Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\=\left(3-4\right)+\left(-3-7\right)i\\Refine\\=-1-10i

Number 3: (-5+2i)+(-2+8i)

Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\=\left(-5-2\right)+\left(2+8\right)i\\Refine\\=-7+10i

8 0
3 years ago
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