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Marianna [84]
4 years ago
10

Complete the table by filling in the formula for the ionic compound formed by each pair of cations and anions, as shown for the

first pair. ion k+ nh+4 mg2+ fe3+ cl− kcl oh− co2−3 po3−4
Chemistry
2 answers:
Kitty [74]4 years ago
6 0
In chemistry, the elements that exist with electrical charges are called ions. These ions can carry a positive charge, for which they are called cations, or a negative charge, for which they are called anions. These ions carry an electric charge because they do not conform to the stable number of electrons of their neutral atom. Because of this, they carry excess electrons for cations, and a lack of electrons for the anions.

When cations and anions form together such that there is a complete transfer of electrons so that each ion would be neutral, an ionic bond is formed. If you write the reaction, the superscripts and subscripts would just cross-multiply. If the cation is A⁺ᵃ, and the anion is B⁻ˣ, then the ionic compound would then be AₓBₐ. Of x=a, then they will cancel out which will yield AB. Therefore, the ionic compound for each pair of ions are:

NH₄⁺ + OH⁻ = NH₄OH
Mg²⁺ + CO₃²⁻ = MgCO₃
Fe³⁺ + PO₃⁴⁻ = Fe₄(PO₃)₃
kolezko [41]4 years ago
3 0

The ionic compounds formed are: NH_{4}OH, \ MgCO_{3}, \ and \ FePO_{4}.

<h3>FURTHER EXPLANATION</h3>

Ionic compounds are made up of ion pairs (cation - anion).

<h3><u>Ions</u></h3>

Ions are atoms that gained or lost electrons and have become charged. Atoms become positively charged when they lose one or more electrons and negatively charged when they gain extra electrons. Cations are positively charged ions while anions are negatively charged.  

Ions may also be monatomic or polyatomic. Monatomic ions are made up of only one element. A polyatomic ion is a group of elements covalently bonded to each other but the entire unit is charged.

<h3 /><h3><u>Formulas of Ionic Compounds</u></h3>

Ionic compounds are neutral substances. They have a net charge of zero resulting from the balanced charges of the cations and anions. With this in mind, when writing the chemical formula of ionic compounds, the total positive charge due to the cation must be equal to the total negative charge due to the anion and their sum should be zero.

<h3><u>Criss-cross Method</u></h3>

The steps in writing the chemical formula are as follows with an example for Li^{+} \ and \ O^{2-}:

  • Write the chemical symbol of the cation but do not include the charge (or superscript). Beside it write the symbol for the anion without the charge.

        Ex: Li O

  • Beside the cation symbol, write as a subscript, the numeric value of the charge of the anion. Do not include the sign.

        Ex. Since the charge of the anion O2- is -2, write 2 as the

        subscript of  Li : Li_{2}O

  • As a subscript beside the anion, write the numeric value of the charge of the cation. Do not include the sign.

         Ex. Since the charge of Li+ is +1, the subscript beside O    

         will be 1.  When the subscript is supposed to be 1, it is not

         written but simply implied ( by not putting any subscript at

         all):  Li_{2}O

  • Check if the net charge of the compound is zero by getting the sum of the charge of each ion multiplied by its subscript. If not, double check the subscripts.

       <em> Net charge = 2(+1) + (-2) = 0.</em>

1. NH_{4}^{+} \ and \ OH^{-}

Since the polyatomic cation has a +1 charge and the polyatomic anion has a -1 charge, having one of each group balances the charges. Therefore, the formula is NH_{4}OH.

2. Mg^{2+} \ and \ CO_{3}^{2-}

The cation has a charge of +2 and the carbonate anion has a charge of -2. The net charge will be zero if one of each is in the formula unitMgCO_{3}.

3. Fe^{3+} \ and \ PO_{4}^{3-}

The cation has a +3 charge and the phosphate ion has a -3 charge. Their charges cancel when one cation and one anion is in the formula unit which is FePO_4.

<h3>LEARN MORE</h3>
  • ion formation brainly.com/question/6177640
  • covalent compound brainly.com/question/8711546
  • naming ionic compounds brainly.com/question/7193259

Keywords: chemical formula, ions, ionic compound

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jeka57 [31]
a) when Kc = concentration of products / concentration of reactants
  So according  to the reaction equation:
Br2(g) + Cl2(g) → 2BrCl(g)

∴ Kc =[BrCl] ^2 / [Br2][Cl2]

b) when q = [BrCl]^2 / [Br2][Cl2]
and we have [BrCl] = 3 m 
[Br2] = 1 m 
[Cl2] = 1 m
So by substitution:
q= 3^2 / 1*1 = 9 

- and we can see that q > Kc 
the reaction is not at equilibrium that means there are more products and the reaction shifts to the left to increase the reactants and decrease the products to achieve equilibrium.

C) by using ICE table:

              Br2(g) + Cl2(g) → 2BrCl (g)
initial       1               1               3
change  -X              -X            +X
Equ       (1-X)          (1-X)         (3+X)

when Kc = [Brcl]^2/[Cl2][Br2]
by substitution:
7 = (3+X)^2 / (1+X) (1+X)  by solving this equation for X
∴X = 0.215
so at equilibrium:
∴ [Br2] = [Cl2] = 1-0.215 = 0.785 m 
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4 0
4 years ago
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Do your structures resemble the following?<br> H-C=C-H
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3 0
3 years ago
A 1.25 g sample of aluminum is reacted with 3.28 g of copper (II) sulfate. What is the limiting reactant?
KengaRu [80]

Answer:

d. Copper (II) sulfate

Explanation:

Given data:

Mass of Al = 1.25 g

Mass of CuSO₄ = 3.28 g

What is limiting reactant = ?

Solution:

Chemical equation:

2Al + 3CuSO₄   →   Al₂ (SO₄)₃ + 3Cu

Number of moles of Al:

Number of moles = mass/molar mass

Number of moles = 1.25 g/ 27 g/mol

Number of moles = 0.05 mol

Number of moles of CuSO₄:

Number of moles = mass/molar mass

Number of moles = 3.28 g/ 159.6 g/mol

Number of moles = 0.02 mol

now we will compare the moles of reactant with product.

               Al           :           Al₂ (SO₄)₃

                 2          :             1

               0.05       :          1/2×0.05=0.025 mol

                Al           :            Cu

                 2            :              3

               0.05         :            3/2×0.05 = 0.075 mol

         CuSO₄           :           Al₂ (SO₄)₃

                3             :             1

               0.02         :          1/3×0.02=0.007 mol

         CuSO₄           :            Cu

               3               :              3

               0.02         :              0.02

Less number of moles of reactants are produced by CuSO₄ thus it will act as limiting reactant.

4 0
3 years ago
You apply the same amount of heat to five grams of water and five grams of aluminum. The temperature of the aluminum increases m
Mashutka [201]
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Motion requires energy: The more energy matter has the higher temperature it will also have. Typicall this energy is supplied by heat. Heat loss or gain by matter is equivalent energy loss or gain.

With the observation above understood we con now ask the following question: by how much will the temperature of an object increase or decrease by the gain or loss of heat energy? The answer is given by the specific heat (S) of the object. The specific heat of an object is defined in the following way: Take an object of mass m, put in x amount of heat and carefully note the temperature rise, then S is given by



In this definition mass is usually in either grams or kilograms and temperatture is either in kelvin or degres Celcius. Note that the specific heat is "per unit mass". Thus, the specific heat of a gallon of milk is equal to the specific heat of a quart of milk. A related quantity is called the heat capacity (C). of an object. The relation between S and C is C = (mass of obect) x (specific heat of object). A table of some common specific heats and heat capacities is given below:

Some common specific heats and heat capacities: Substance S (J/g 0C) C (J/0C) for 100 g Air 1.01 101 Aluminum 0.902 90.2 Copper 0.385 38.5 Gold 0.129 12.9 Iron 0.450 45.0 Mercury 0.140 14.0 NaCl 0.864 86.4 Ice 2..03 203 Water 4.179 417.9   

Consider the specific heat of copper , 0.385 J/g 0C. What this means is that it takes 0.385 Joules of heat to raise 1 gram of copper 1 degree celcius. Thus, if we take 1 gram of copper at 25 0C and add 1 Joule of heat to it, we will find that the temperature of the copper will have risen to 26 0C. We can then ask: How much heat wil it take to raise by 1 0C 2g of copper?. Clearly the answer is 0.385 J for each gram or 2x0.385 J = 0.770 J. What about a pound of copper? A simple way of dealing with different masses of matter is to dtermine the heat capacity C as defined above. Note that C depends upon the size of the object as opposed to S that does not.

We are not in position to do some calculations with S and C.

Example 1: How much energy does it take to raise the temperature of 50 g of copper by 10 0C?



Example 2: If we add 30 J of heat to 10 g of aluminum, by how much will its temperature increase?

 



Thus, if the initial temperture of the aluminum was 20 0C then after the heat is added the temperature will be 28.3 0C.
5 0
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