333,000 Joules is the amount of energy (heat) in joules required to raise the temperature of 5 kg of iron from 50°C to 200°C.
Explanation:
Data given:
mass of iron 5 Kg or 5000
initial temperature = 50 degree centigrade
final temperature = 200 degrees centigrade
change in temperature (Δ T= 200 -50 degrees centigrade)
= 150 °C
cp (specific heat capacity of iron) = 0.444j/gram C
q (heat supplied) = ?
applying the formula,
q=mcΔT
putting the values in the equation:
q = 5000 X 0.444 X150
q = 333,000 Joules of energy.
The heat required 333,000 Joules of energy is required.
Answer is: <span>volume of 1 M NaOH is 1 ml.
</span>c₁(NaOH) = 1 M.
V₂(NaOH) = 10 ml.
c₂(NaOH) = 0,1 M.
V₁(NaOH) = ?
c₁ - original concentration of the solution, before it gets diluted.
c₂ - final concentration of the solution, after dilution.
V₁ - <span>volume to be diluted.
V</span>₂ - <span>final volume after dilution.
c</span>₁ · V₁ = c₂ · V₂.
V₁(NaOH) = c₂ · V₂ ÷ c₁.
V₁(NaOH) = 0,1 M · 10 ml ÷ 1 M.
V₁(NaOH) = 1 ml.
The answer is 1) mixing of two gases by diffusion.
Once 2 gases are mixed by diffusion, they cannot be obtained from the mixture of gases. Hence, it is considered to be an irreversible process.
