1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ad-work [718]
2 years ago
12

Which of the following is true?

Chemistry
2 answers:
kotykmax [81]2 years ago
6 0
Anwser is C for cesium
Inessa05 [86]2 years ago
6 0

Answer:

D. Lithium is the least reactive element in group 1, because it is the smallest and holds its valence electron more tightly than the others in the same group.

Explanation:

Lithium is at the top of group one and has only two energy levels. It has the smallest atomic radius of all the elements in group one. This means it's valence electron is the closest one to the nucleus of all the group 1 elements. The nucleus holds this electron more tightly than other group 1 nuclei which is why lithium is the least reactive of all the group 1 metals.

You might be interested in
Help anyone please ;)<br> will mark brainliest!!<br> thank you lol &lt;3
Usimov [2.4K]

Answer:

The answer to your question is below

Explanation:

2.- 6

3.- Carbon

4.- These electrons can be share to obtain stability.

5.- Protons, electrons

6.- electron cloud

7.- I and III

8.- 1

9.- 8A

10.- 4

11.- F

12.- F

13.- F

14.- T

15.- T

16.- T

17.- T

18.- T (I can not read the question but I think is true)

5 0
3 years ago
Read 2 more answers
What is Li+1 atomic mass
zvonat [6]

Answer:

7.941

Explanation:

You can look at a picture of the periodic table.To calculate the atomic mass of a single atom of an element, add up the mass of protons and neutrons. Example: Find the atomic mass of an isotope of carbon that has 7 neutrons. You can see from the periodic table that carbon has an atomic number of 6, which is its number of protons.

Hope I helped

3 0
3 years ago
What are the molality and mole fraction of solute in a 22.3 percent by mass aqueous solution of formic acid (HCOOH)?
Vanyuwa [196]

Answer:

Mole fraction for solute = 0.1, or 10%

Molality = 6.24 mol/kg

Explanation:

22.3% by mass → In 100 g of solution, we have  22.3 g of HCOOH

Mass of solution = 100 g

Mass of solute = 22.3 g

Mass of solvent = 100 g - 22.3g = 77.7 g

Let's convert the mass to moles

22.3 g . 1mol/ 46 g = 0.485 moles

77.7 g. 1mol / 18 g = 4.32 moles

Total moles = 4.32 moles + 0.485 moles = 4.805 moles

Xm for solute = 0.485 / 4.805 = 0.100 → 10%

Molality → mol/ kg → we convert the mass of solvent to kg

77.7 g.  1 kg / 1000g = 0.0777 kg

0.485 mol / 0.0777 kg = 6.24 m

6 0
3 years ago
Read 2 more answers
How long does it take for a 12.62g sample of ammonia to heat from 209K to 367K if heated at a constant rate of 6.0kj/min? The me
Georgia [21]
First, consider the steps to heat the sample from 209 K to 367K.

1) Heating in liquid state from 209 K to 239.82 K

2) Vaporaizing at 239.82 K

3) Heating in gaseous state from 239.82 K to 367 K.


Second, calculate the amount of heat required for each step.

1) Liquid heating

Ammonia = NH3 => molar mass = 14.0 g/mol + 3*1g/mol = 17g/mol

=> number of moles = 12.62 g / 17 g/mol = 0.742 mol

Heat1 = #moles * heat capacity * ΔT

Heat1 = 0.742 mol * 80.8 J/mol*K * (239.82K - 209K) = 1,847.77 J

2) Vaporization

Heat2 = # moles * H vap

Heat2 = 0.742 mol * 23.33 kJ/mol = 17.31 kJ = 17310 J

3) Vapor heating

Heat3 = #moles * heat capacity * ΔT

Heat3 = 0.742 mol * 35.06 J / (mol*K) * (367K - 239.82K) = 3,308.53 J

Third, add up the heats for every steps:

Total heat = 1,847.77 J + 17,310 J + 3,308.53 J = 22,466.3 J

Fourth, divide the total heat by the heat rate:

Time = 22,466.3 J / (6000.0 J/min) = 3.7 min

Answer: 3.7 min


3 0
3 years ago
How much heat was transferred from 50.0 g of water if the temperature of the water went from 30.0 ° C to 55.0 °? The specific he
Lena [83]

Answer:

Heat transfer = Q = 62341.6 J

Explanation:

Given data:

Heat transfer = ?

Mass of water = 50.0 g

Initial temperature = 30.0°C

Final temperature = 55.0°C

Specific heat capacity of water = 4.184 J/g.K

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 55.0°C -  30.0°C

ΔT = 25°C (25+273= 298 K)

Q = 50.0 g × 4.184 J/g.K ×298 K

Q = 62341.6 J

4 0
3 years ago
Other questions:
  • Can someone explain to me what I'm doing wrong? 68mL was wrong as well. Selecting "tenths place" for 3a and "hundredths place" f
    9·1 answer
  • Some people argue that a policy of putting out wildfires is having a negative long-term effect on the number and strength of wil
    7·1 answer
  • What happens to the temperature of water when the average kinetic energy of its particles decreases
    9·1 answer
  • Which is more prevalent in the food we eat: carbon-12 or carbon-14?
    8·1 answer
  • Magnesium is able to ____ copper, and copper is able to ____ magnesium.
    10·1 answer
  • It is necessary to know the time of day and the position of the Sun or the stars relative to one's longitude line because ____.
    9·1 answer
  • Calculate the volume of 2.408x1024 molecules of water vapor at STP.
    8·1 answer
  • A.) What is the mass in g of 5 mols of Mg?
    5·1 answer
  • If you have 3 moles of calcium carbonate, how many grams of calcium bicarbonate are formed?
    7·1 answer
  • Based on the information in the tables, what is the Enthalpy of the solution for each substance? Please help me with this proble
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!