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FinnZ [79.3K]
3 years ago
7

NASA communicates with the Space Shuttle and International Space Station using Ku-band microwave radio. Suppose NASA transmits a

microwave signal to the Space Shuttle using radio waves with a frequency of 13.GHz. Calculate the wavelength of these radio waves.
Chemistry
1 answer:
Tanya [424]3 years ago
8 0

Answer:

A = 0.023 m

Explanation:

The relation between the frequency of a radiation and its wavelength is given by the following expression.

where,

c is the speed of light (it has a constant value of 3.00 x 108 m/s)

A is the wavelength of the radiation v is the frequency of the radiation

In this case, the frequency is 13 GHz = 13 x

10° Hz = 13 x 1o° s-

The wavelength associated with this frequency is:

A = c/v = (3.00 x 10° m/s)/(13 x 10° s-") = 0.023

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Made up of the protons and neutrons, this part or the atom contains nearly all the mass of the atom
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Answer:

The nucleus

Explanation:

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Who goes to K12 and if so what grade
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I might next year with my cuz and nex year ima be in 8th

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Read 2 more answers
If 5,800 j of energy are applied to a 15.2 kg piece of lead, by how much does the temp change if the specific heat of lead is 0.
scoray [572]

Answer:

The answer will be 2.98K

Explanation:

Using the formula:

Q = mc∆T

Q= 5,800 (heat in joules)

m= convert 15.2kg to g which is 15200g (mass in grams)

c= 0.128 J/g °c (Specific heat capacity)

∆T=  what we need to find (temperature change)

5800J = 15200g x 0.128 x ∆T

= 2.98K  

7 0
3 years ago
How many grams of propanol (C3H7OH, 60.10 g/mol) would be needed to make 750 mL of a solution with an osmotic pressure of 25 atm
Ierofanga [76]
Answer:

= 46.06 grams

Explanation:

P=cRT

25 = c (0.0821)(298)

concentration = c = 1.021 M

number of moles = (1.021)(0.75) = 0.7664 moles

mass = (0.7664)(60.10)=40.06 grams
3 0
3 years ago
Suppose a student started with 142.0 mg of trans-cinnamic acid, 412 mg of pyridinium tribromide, and 2.30 mL of glacial acetic a
nirvana33 [79]

Answer: Theoretical Yield = 0.2952 g

               Percentage Yield = 75.3%

Explanation:

Calculation of limiting reactant:

n-trans-cinnamic acid moles = (142mg/1000) / 148.16 = 9.584*10⁻⁴ mol

pyridium tribromide moles = (412mg/1000) / 319.82= 1.288*10⁻³ mol

  • n-trans-cinnamic acid is the limiting reactant

The molar ratio according to the equation mentioned is equals to 1:1

The brominated product moles is also = 9.584*10⁻⁴ mol

Theoretical yield = (9.584*10⁻⁴ mol) * (Mr of brominated product)

                             =  (9.584*10⁻⁴ mol) * (307.97) = 0.2952 g

Percentage Yield is : Actual Yield / Theoretical Yield = 0.2223/0.2952

                                                                                           = 75.3%

4 0
4 years ago
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