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FinnZ [79.3K]
3 years ago
7

NASA communicates with the Space Shuttle and International Space Station using Ku-band microwave radio. Suppose NASA transmits a

microwave signal to the Space Shuttle using radio waves with a frequency of 13.GHz. Calculate the wavelength of these radio waves.
Chemistry
1 answer:
Tanya [424]3 years ago
8 0

Answer:

A = 0.023 m

Explanation:

The relation between the frequency of a radiation and its wavelength is given by the following expression.

where,

c is the speed of light (it has a constant value of 3.00 x 108 m/s)

A is the wavelength of the radiation v is the frequency of the radiation

In this case, the frequency is 13 GHz = 13 x

10° Hz = 13 x 1o° s-

The wavelength associated with this frequency is:

A = c/v = (3.00 x 10° m/s)/(13 x 10° s-") = 0.023

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What volume, in mL, of carbon dioxide gas is produced at STP by the decomposition of 0.242 g calcium carbonate (the products are
damaskus [11]

Answer:

54.21 mL.

Explanation:

We'll begin by calculating the number of mole in 0.242 g calcium carbonate, CaCO3.

This is illustrated below:

Mass of CaCO3 = 0.242 g

Molar mass of CaCO3 = 40 + 12 +(16x3) = 40+ 12 + 48 = 100 g/mol

Mole of CaCO3 =?

Mole = mass /Molar mass

Mole of CaCO3 = 0.242/100

Mole of CaCO3 = 2.42×10¯³ mole.

Next, we shall write the balanced equation for the reaction. This is given below:

CaCO3 —> CaO + CO2

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole CaO and 1 mole of CO2.

Next, we shall determine the number of mole of CO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole of CO2.

Therefore,

2.42×10¯³ mole of CaCO3 will also decompose to produce 2.42×10¯³ mole of CO2.

Therefore, 2.42×10¯³ mole of CO2 were obtained from the reaction.

Finally, we shall determine volume occupied by 2.42×10¯³ mole of CO2.

This can be obtained as follow:

1 mole of CO2 occupies 22400 mL at STP.

Therefore, 2.42×10¯³ mole of CO2 will occupy = 2.42×10¯³ x 22400 = 54.21 mL

Therefore, 54.21 mL of CO2 were obtained from the reaction.

7 0
3 years ago
Bismuth has a density of 9.80 g/cm^ 3 . What is the of 3.74 cm ^ 3 of Bi?
Ierofanga [76]

Explanation:

density = mass/ volume

mass= density × volume

mass= 9.80× 3.74

mass= 36.652 g

3 0
3 years ago
Calculate the mass of nitric acid required to make a 250mL solution with 2.40 ph
meriva

The mass of nitric acid required to make the given solution is 0.0627 g.

The given parameters:

  • <em>Volume of the acid, V = 250 mL</em>
  • <em>pH of the acid, = 2.4</em>

The hydrogen ion (H⁺) concentration of the nitric acid is calculated as follows;

H^+ = 10^{-pH}\\\\H^+ = 10^{-2.4}\\\\H^+ = 0.00398

The molarity of the nitric acid is calculated as follows;

=  0.00398 \ H^+ \times \frac{1 \ M \ HNO_3}{1 \ H^+} \\\\= 0.00398 \ M

The number of moles of the nitric acid is calculated as follows;

moles = M\times L\\\\moles = 0.00398\ M \ \times \ \frac{250 \ mL}{1000} \\\\moles = 9.95 \times 10^{-4} \ mol.

The molar mass of nitric acid is calculated as;

HNO_3 = (1) \ + (14) \ + (16 \times 3) = 63 \ g/mol

The mass of the nitric acid contained in the calculated number of moles is calculated as;

mass = moles\  \times \ molar \ mass\\\\mass = 9.95\times 10^{-4} \ mol. \ \times \ 63 \ g/mol\\\\mass = 0.0627 \ g

Thus, the mass of nitric acid required to make the given solution is 0.0627 g.

Learn more about molarity of acids here: brainly.com/question/13864682

3 0
2 years ago
Does an object appear larger when the observer is closer or farther away from it?
ExtremeBDS [4]
Place your hand in front of your face. Now push it away from your body. Which looked bigger?
3 0
3 years ago
What is a reliable measurement
gavmur [86]
A dependible common measurement
3 0
3 years ago
Read 2 more answers
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