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FinnZ [79.3K]
2 years ago
7

NASA communicates with the Space Shuttle and International Space Station using Ku-band microwave radio. Suppose NASA transmits a

microwave signal to the Space Shuttle using radio waves with a frequency of 13.GHz. Calculate the wavelength of these radio waves.
Chemistry
1 answer:
Tanya [424]2 years ago
8 0

Answer:

A = 0.023 m

Explanation:

The relation between the frequency of a radiation and its wavelength is given by the following expression.

where,

c is the speed of light (it has a constant value of 3.00 x 108 m/s)

A is the wavelength of the radiation v is the frequency of the radiation

In this case, the frequency is 13 GHz = 13 x

10° Hz = 13 x 1o° s-

The wavelength associated with this frequency is:

A = c/v = (3.00 x 10° m/s)/(13 x 10° s-") = 0.023

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A molecule that oxidized gains electrons and energy. true or false
quester [9]
I suppose it false, since the oxidation involves the loss or removal of the electrons such forth it does not gain electrons.
5 0
3 years ago
Suppose a gas mixture used for anesthesia contains 4.60 mol oxygen (O₂) and 6.00 mol nitrous oxide (N₂O). The total pressure of
julia-pushkina [17]

Considering the definition of mole fraction, the mole fraction of O₂ in the mixture is 0.434.

<h3>Definition of mole fraction</h3>

The molar fraction is a way of measuring the concentration that expresses the proportion in which a substance is found with respect to the total moles of the solution.

In other words, the mole fraction expresses the concentration of solute in a solution as the ratio of moles of substance to total moles of solution:

mole fraction=\frac{moles of substance}{moles of solution}

<h3>Mole fraction of O₂ in this mixture</h3>

In this case, you know a gas mixture used for anesthesia contains 4.60 mol oxygen (O₂) and 6.00 mol nitrous oxide (N₂O).

So, the total moles of the solution can be calculated as:

Total moles = moles of oxygen (O₂) + moles of nitrous oxide (N₂O)

Then:

Total moles= 4.60 moles + 6 moles

Total moles= 10.60 moles

Finally, the more fraction of O₂ can be calculated as follow:

Mole fraction of O_{2} =\frac{moles of O_{2}}{total moles}

Mole fraction of O_{2} =\frac{4.60 moles}{10.6o moles}

Solving:

<u><em>Mole fraction O₂ = 0.434</em></u>

Finally, the mole fraction of O₂ in the mixture is 0.434.

Learn more about mole fraction:

brainly.com/question/14434096

brainly.com/question/10095502

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3 0
2 years ago
A device that does work with only one movement and changes the size or direction of a force is a(n) ____.
worty [1.4K]

Answer:

A device that does work with only one movement and changes the size or direction of a force is a simple machine.

Explanation:

  • For applying force, any used basic mechanical devices are simple machines.
  • Simple machine changes the direction as well as the amplitude of the applied force i.e. we can increase or decrease the magnitude of the force.
  • A simple machine is the most basic mechanism to use the force as we need in big mechanical machines.
  • Some of the examples of simple machines are inclined plane, lever, wedge, wheel and axle, pulley, and screw.
6 0
3 years ago
The molecular clock theory uses genetic traits to estimate how long ago various groups of organisms diverged evolutionary from o
Nataliya [291]
<span>Many scientific investigations have provided evidence to support this as the best explanation of the data</span>
8 0
2 years ago
Read 2 more answers
What volume will 1.27 moles of helium gas occupy at 80.00 °C and 1.00 atm?
White raven [17]

Answer:

36.8 L

Explanation:

We'll begin by converting 80 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 80 °C

T(K) = 80 + 273

T(K) = 353 K

Finally, we shall determine the volume occupied by the helium gas. This can be obtained as follow:

Number of mole (n) = 1.27 moles

Temperature (T) = 353 K

Pressure (P) = 1 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

PV = nRT

1 × V = 1.27 × 0.0821 × 353

V = 36.8 L

Thus, the volume occupied by the helium gas is 36.8 L

5 0
3 years ago
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