1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
k0ka [10]
3 years ago
12

What is the ratio of effusion rates of krypton and neon at the same temperature and pressure?

Chemistry
2 answers:
vfiekz [6]3 years ago
8 0

<u>Answer:</u> The ratio of effusion rates of krypton and neon is 0.49

<u>Explanation:</u>

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

We are given:

Molar mass of Neon = 20.18 g/mol

Molar mass of Krypton = 83.80 g/mol

By taking their ratio, we get:

\frac{Rate_{Kr}}{Rate_{Ne}}=\sqrt{\frac{M_{Ne}}{M_{Kr}}}

\frac{Rate_{Kr}}{Rate_{Ne}}=\sqrt{\frac{20.18}{83.80}}\\\\\frac{Rate_{Kr}}{Rate_{Ne}}=0.49

Hence, the ratio of rate of effusion of krypton and neon will be 0.49

egoroff_w [7]3 years ago
7 0
The formula we use would be the graham's law. We do as follows:

<span>E_Kr / E_Ne = sqrt ( M_Ne / M_Kr) 
</span>
<span>= sqrt ( 20.1797 g/mol / 83.798 g/mol ) </span>
<span>= sqrt (0.24081) </span>
<span>= 0.4907
</span>
Hope this answers the question. Have a nice day.
You might be interested in
How is copper that is suitable for making electrical wires produced?
patriot [66]
Copper is a good conductor of heat and electricity so it will not fry easily
4 0
4 years ago
Which of the following instruments has the highest pitch?<br> bass drum<br> flute<br> trombone
sweet [91]

Answer:

Flute

Explanation:

7 0
3 years ago
Read 2 more answers
given that 32.0g sulphur contains 6.02×10^23 sulphur atoms,how many atoms are there in 2.70g of aluminum​
dangina [55]

Answer:

6.022 × 10²² atoms

Explanation:

Generally 1 mol of any element contains 6.02×10^23  atoms. The number 6.022 × 10²³ is known as Avogadro's number.

Mass of Aluminium = 2.70g

Molar mass = 27g/mol

Number of moles = Mass / Molar mass = 2.70 / 27 = 0.1 mol

1 mol =  6.022 × 10²³

0.1 mol = x

x = 6.022 × 10²³ * 0.1 = 6.022 × 10²² atoms

5 0
3 years ago
Do you think a battery system would OR wouldn’t have energy? If so, give me evidence/observations as to why you think so.
Basile [38]

Answer:

Yes it would

Explanation: Well it kinda depend on the voltage and how the battery has been in use or based on the condition

6 0
3 years ago
If I have 12 protons, how many neutrons and electrons would I need to make a stable atom?
lesantik [10]

Answer:

im pretty sure you need 15 in all but dont get mad it thats wrong, so you would i think need 3 neutrons

Explanation:

3 0
3 years ago
Other questions:
  • The activation energy for a given reaction is 56 kj/mol. at what temperature would the rate constant be quadruple what is was at
    8·1 answer
  • Helpppp me plzz....
    6·1 answer
  • What does one mole of H2O correspond to?
    10·2 answers
  • Which effect of long-term environmental change is the driving force behind evolution?​
    15·1 answer
  • When magnesium reacts with sulfuric acid the products are magnesium sulfate and hydrogen. If there are 15 grams of magnesium at
    14·1 answer
  • What is the term for metabolic pathways that use ATP to synthesize complex molecules from smaller components?
    10·1 answer
  • A process with a negative change in enthalpy and a negative change in entropy will generally be: _________________
    14·1 answer
  • How many total atoms are in K2(H2AsO4)2<br> 5<br> 18<br> 16<br> 12
    8·1 answer
  • What are 6 things you would do to a new substance to determine if it was a metal? I need help!
    5·2 answers
  • (1.) If at 100.0 mL solution contains 0.850 moles of a solute, what is the molarity ?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!