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k0ka [10]
2 years ago
12

What is the ratio of effusion rates of krypton and neon at the same temperature and pressure?

Chemistry
2 answers:
vfiekz [6]2 years ago
8 0

<u>Answer:</u> The ratio of effusion rates of krypton and neon is 0.49

<u>Explanation:</u>

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

We are given:

Molar mass of Neon = 20.18 g/mol

Molar mass of Krypton = 83.80 g/mol

By taking their ratio, we get:

\frac{Rate_{Kr}}{Rate_{Ne}}=\sqrt{\frac{M_{Ne}}{M_{Kr}}}

\frac{Rate_{Kr}}{Rate_{Ne}}=\sqrt{\frac{20.18}{83.80}}\\\\\frac{Rate_{Kr}}{Rate_{Ne}}=0.49

Hence, the ratio of rate of effusion of krypton and neon will be 0.49

egoroff_w [7]2 years ago
7 0
The formula we use would be the graham's law. We do as follows:

<span>E_Kr / E_Ne = sqrt ( M_Ne / M_Kr) 
</span>
<span>= sqrt ( 20.1797 g/mol / 83.798 g/mol ) </span>
<span>= sqrt (0.24081) </span>
<span>= 0.4907
</span>
Hope this answers the question. Have a nice day.
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wariber [46]

Answer:

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Explanation:

The question is asking to write the <em>isotopic symbol </em>of the form ^A_ZX for the <em>sodium isotope with 13 neutrons</em>.

In general, the isotopic symbol in the given form shows:

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The atomic number, or number of protons, is the same for every isotope of the element, and you can find it in any periodic table. Tha atomic number of sodium is 11. Thus:

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Alik [6]

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Read 2 more answers
Please help me and explanation would be really awesome thank you!
valentina_108 [34]

Answer:

So the answer would be 10 moles

Explanation:

1) Start with the molecular formula for water: H_{2} O!

2) If there are 10 moles of water use a mole ratio to calculate the moles of oxygen it would produce.

(This question is... interesting... since they chose an element that is diatomic in free state so It could TECHNICALLY be two answers, moles of O or moles of O_{2})

The mole ratio is 1 moles of H_{2}O to 1 moles of O. This is because the coefficient for oxygen in water is simple 1, so the ratio is 1:1.

3) that means if 10 moles of water decompose, they decompose into 10 moles of H_{2} and 10 moles of O.

Extra:

About what I was saying before about the question being slightly interesting:

10 moles of pure oxygen is produced but free state oxygen exists as O_{2} so it could possibly be 10 OR 5! However, notice it says elements. This leads me to believe the answer is 10 (monatomic oxygen) instead of 5 (free state/diatomic oxygen).

I hope this helps!

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