Answer:
x = 
Step-by-step explanation:
Given equation is,
ax + 3 = 23
To solve this equation for the value of x isolate the variable 'x' on the one side of the equation.
Step 1,
Subtract 3 from both the sides of the equation.
ax + 3 - 3 = 23 - 3
ax = 20
Step 2,
Divide the equation by a,

x = 
Therefore, x =
will be the answer.
(A)
P(<em>X</em> < 61.25) = P((<em>X</em> - 55.4)/4.1 < (61.25 - 55.4)/4.1)
… ≈ P(<em>Z</em> ≤ 0.1427)
… ≈ 0.5567
(B)
P(<em>X</em> > 46.5) = P((<em>X</em> - 55.4)/4.1 > (46.5 - 55.4)/4.1)
… ≈ P(<em>Z</em> > -2.1707)
… ≈ 1 - P(<em>Z</em> ≤ -2.1707)
… ≈ 0.9850
Answer:
a balance and a beaker of water
hope it helps mark as brainliest
Answer:
Step-by-step explanation:
The formula for determining the area of a rectangle is expressed as
Area = 2(L + W)
Where
L represents the length of the rectangle.
W represents the width of the rectangle.
A proper rectangle has a length of 6 inches and a with of 8 inches. The area of the rectangle would be
6 × 8 = 48 inches^2
A square with a side length of 3 inches was cut of it. The formula for determining the area of a square is l^2
Therefore,
Area of square = 3^2 = 9 inches ^2
The area of the remaining paper would be
48 - 9 = 39 inches^2
The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.