I pretty sure it’s (C) it’s volume will increase.
I hope this helped!
Answer:
i think its C im not so sure
Explanation:
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Answer:
NH3 weak base
HCOOH weak acid
H3PO4 weak acid
NaOH strong base
Explanation:
When talking about the weakness or strength of acid and bases, it is essential to look at it from the base point of ionization or dissociation in solutions. For an acid or base to be termed strong , this means it ionize completely in solution to form hydroxonium ion and hydroxide jobs respectively in water. For an acid or base to be termed weak, it ionizes only partially in solution.
The strength of acid can be accessed from the value of the acid ionization constant Ka. Strong acids like sulphuric acid have a fairly large value for for this constant while weak acids have a relatively low value for this constant. Hence, we must know that the dissociation equation is not enough to say an acid is weak or strong. Acids with higher Ka value are stronger with acids with lower Ka value.
In likewise manner, we have the base dissociation constant. It is the equilibrium constant for a base dissociation reaction. While stronger bases have relatively higher values for Ka, weak bases have a relatively lower value.
Ammonia yields a weak base solution of ammonium hydroxide in water. This makes it a weak acid
Methanoic or Formic acid like most organic acid is a weak acid. It ionizes only partially in solutions.
Phosphoric acid is also a weak acid as it ionizes partially in solutions too.
Lastly, sodium hydroxide is a strong base as it ionizes completely in solution
Answer: The correct answer is -297 kJ.
Explanation:
To solve this problem, we want to modify each of the equations given to get the equation at the bottom of the photo. To do this, we realize that we need SO2 on the right side of the equation (as a product). This lets us know that we must reverse the first equation. This gives us:
2SO3 —> O2 + 2SO2 (196 kJ)
Remember that we take the opposite of the enthalpy change (reverse the sign) when we reverse the equation.
Now, both equations have double the coefficients that we would like (for example, there is 2S in the second equation when we need only S). This means we should multiply each equation (and their enthalpy changes) by 1/2. This gives us:
SO3 —>1/2O2 + SO2 (98 kJ)
S + 3/2O2 —> SO3 (-395 kJ)
Now, we add the two equations together. Notice that the SO3 in the reactants in the first equation and the SO3 in the products of the second equation cancel. Also note that O2 is present on both sides of the equation, so we must subtract 3/2 - 1/2, giving us a net 1O2 on the left side of the equation.
S + O2 —> SO2
Now, we must add the enthalpies together to get our final answer.
-395 kJ + 98 kJ = -297 kJ
Hope this helps!
The wavelength of reflected light, think of the symbol of Pink Floyd when thinking about light and color