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MrMuchimi
4 years ago
8

How many pairs of electrons are shared between two nitrogen atoms in the formula for hydrazine

Chemistry
1 answer:
Sladkaya [172]4 years ago
8 0
1 pairs of electrons are shared .

image attached ..

hope this helps!

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Why do scientists use models?
Brut [27]
Because it is a representation of data or maybe an object/process that is used to describe a certain data of phenomena that cannot be figured out directly. 
4 0
3 years ago
We usually think of wires as perfect (R=0) conductors, which is not quite accurate. Real wires have resistance, and an effort is
SSSSS [86.1K]

Answer:

Length of copper wire is 5,22m and the diameter of copper wire is 2,14x10⁻³m.

Explanation:

The resistance of a wire is determined by:

R = ρL/A

Where R is resistance (25x10⁻³Ω); ρ is resistivity (1,72x10⁻⁸Ωm); R is length and A is cross sectional area.

Replacing you will obtain:

1,45x10⁶ m⁻¹ = L/A <em>(1)</em>

$1 of copper are:

$1×\frac{1 lb}{2,69} = 0,37 lb. In kg:

0,37lb×\frac{0,453592kg}{1lb} = 0,169 kg of copper.

As density of copper is 8960 kg/m³. The volume of this amount of copper is:

0,169kg×\frac{1m^{3}}{8960kg} = 1,88x10⁻⁵ m³

The volume of a wire is L×A. Thus:

1,88x10⁻⁵ m³ = L×A<em> (2)</em>

Replacing (1) in (2)

1,88x10⁻⁵ m³ = 1,45x10⁶ m⁻¹A²

A = 3,6x10⁻⁶ m²

Thus, L = 5,22 m

Thus, <em>length of copper wire is 5,22 m</em>

As area = 3,6x10⁻⁶ m² = \frac{pi}{4}d^{2} Where d is diameter.

The <em>diameter of copper wire is 2,14x10⁻³m</em>

I hope it helps!

4 0
3 years ago
How much energy is contained in a particle that has a mass of m = 1 ug
Fudgin [204]

Answer:

90MJ

Explanation:

Energy= mc^2

Where c= speed of light

m= mass of the object

Mass= m = 1 ug ( then we need to convert from micro gram to micro Joule)= 0.000000001

C= 3× 10^8 m/s

E= = [0.000000001 × (3× 10^8 )^2]

E = [0.000000001 × 89 875 517 873 681]

= 89 875 517.9 joule

Then we can convert to megajoules as

90MJ

5 0
3 years ago
Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq), as
zubka84 [21]

Answer:

Explanation:

MnO₂(s) + 4 HCl(aq)  = MnCl₂(aq) + 2 H₂O(l) + Cl₂

87 g                                                                     22.4 x 10³ mL

volume of given chlorine gas at NTP or at 760 Torr and 273 K

=  175 x ( 273 + 25 ) x 715 / (273 x 760 )

= 179.71 mL

22.4 x 10³ mL of chlorine requires 87 g of MnO₂

179.4 mL of chlorine will require    87 x 179.4 / 22.4 x 10³ g

= 696.77 x 10⁻³ g

= 696.77 mg .

6 0
4 years ago
A 25.0 g block of a metal alloy at 100 C is dropped into an insulated flask containing 110 g of ice; 5.30 g of the ice melted. W
mr_godi [17]

Answer:

0.00353J/g/°C

Explanation:

I will assume the temperature of the ice to be approximately 0°C.

Moreover, Heat of fusion of water is 6kJ

Amount of heat used to melt 5.3g of ice = 5.3 x 6 / 18

=1.767g°C

Therefore

1.767 = 25 x specific heat cap. x 200

Specific heat cap. = 1.767/(25x200)

= 0.00353J/g/°C

6 0
3 years ago
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