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aksik [14]
3 years ago
12

A 25.0 g block of a metal alloy at 100 C is dropped into an insulated flask containing 110 g of ice; 5.30 g of the ice melted. W

hat is the specific heat capacity of the alloy
Chemistry
1 answer:
mr_godi [17]3 years ago
6 0

Answer:

0.00353J/g/°C

Explanation:

I will assume the temperature of the ice to be approximately 0°C.

Moreover, Heat of fusion of water is 6kJ

Amount of heat used to melt 5.3g of ice = 5.3 x 6 / 18

=1.767g°C

Therefore

1.767 = 25 x specific heat cap. x 200

Specific heat cap. = 1.767/(25x200)

= 0.00353J/g/°C

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Consider a simple reaction in which a reactant AA forms products: A→productsA→products What is the rate law if the reaction is z
levacccp [35]

Answer :

The rate law expression for zero order reaction will be:

Rate=k[A]^0

The rate law expression for first order reaction will be:

Rate=k[A]^1

The rate law expression for second order reaction will be:

Rate=k[A]^2

Zero order reaction : There is no affect on the rate law.

First order reaction : The rate law becomes doubled.

Second order reaction : The rate law becomes quadrupled.

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The given reaction is:

A\rightarrow Products

The rate law expression for zero order reaction will be:

Rate=k[A]^0

The rate law expression for first order reaction will be:

Rate=k[A]^1

The rate law expression for second order reaction will be:

Rate=k[A]^2

Now we have to determine that if doubling of the concentration of A then the rate of reaction will be:

As we know that the zero order reaction does not depend on the concentration of reactant. So, there is no affect on the rate law.

As we know that the first order reaction depend on the concentration of reactant. So, the rate law becomes doubled.

As we know that the second order reaction depend on the concentration of reactant. So, the rate law becomes quadrupled.

5 0
4 years ago
Hannah does an experiment she has two colorless chemicals that she mixes together in a beaker which of the following indicates t
mrs_skeptik [129]

1.the chemical change color from colorless to purple

2. A yellow gas forms

3.a brown solid forms in the bottom of the beaker

4.the temperature of the chemicals rises 15 Celsius

Explanation:

All of the options are proofs that chemical change has occurred.

A chemical change is one with the following properties:

  • A new kind of matter is usually formed as seen by the gas evolution and the formation of the insoluble precipitate i.e brown solid at the bottom of the beaker.
  • They are not easily reversible.
  • Usually accompanied by energy changes as seen in the rise in temperature.
  • Color changes can also infer chemical changes in a reaction.

learn more:

Chemical change brainly.com/question/9388643

#learnwithBrainly

8 0
3 years ago
In the third period of the periodic table sodium is followed by magnesium aluminum silicon and phosphorus which of these element
wariber [46]
Answer:
            Phosphorous has the smallest atomic size.

Explanation:
                   As we know these elements belong to same period means there valence shell is the same. So moving from left to right along the period the shell number remains constant but the number of protons and electrons increases. So, due to increase in number of protons the nuclear charge increases hence attracts the valence electrons more effectively resulting in the decrease of atomic size.

Elements and their atomic radius are as follow,

<span><span>Magnesium          0.160 nm
</span><span>
Aluminium           0.130 nm
</span><span>
Silicon                  0.118 nm
</span><span>
Phosphorus         <span>0.110 nm</span></span></span>
6 0
4 years ago
What is the density of CO2 at a pressure of 0.0079 atm and 227 K? (These are the approximate atmospheric in Mars)
Strike441 [17]

Answer:

The density is 0.0187 g/L

Explanation:

First thing to do here is to calculate the Volume of 1 mole of CO2 using the ideal gas equation

Mathematically;

PV = nRT

thus V = nRT/P

what we have are;

n = 1 mole

R is the molar has constant = 0.082 L•atm•mol^-1•K^-1

P is the pressure = 0.0079 atm

T is temperature = 227 K

Substituting these values, we have;

V = nRT/P = (1 * 0.082 * 227)/0.0079

V = 2,356.20 dm^3

This means according to the parameters given in the question, the volume of 1 mole of carbon iv oxide is 2,356.20 dm^3

But this is not what we want to calculate

What we want to calculate is the density

Mathematically, we can calculate the density using the formula below;

density = molar mass/molar volume

Kindly recall that the molar mass of carbon iv oxide is 44 g/mol

Thus the density = 44/2356.20 = 0.018674136321195 which is approximately 0.0187 g/L

6 0
4 years ago
styrofoam is made by blowing a gas into a polymer called polystyrene, which in turn is made from styrene. Styrene is 92.26% carb
Mumz [18]

Answer : The molecular of the compound is, C_8H_8

Solution :

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 92.26 g

Mass of H = 100 - 92.26 = 7.74 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Step 1 : convert given masses into moles.

Moles of C = \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{92.26g}{12g/mole}=7.688moles

Moles of H = \frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{7.74g}{1g/mole}=7.74moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{7.688}{7.74}=0.99\approx 1

For H = \frac{7.74}{7.74}=1

The ratio of C : H = 1 : 1

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula = C_1H_1

The empirical formula weight = 1(12) + 1(1) = 13 gram/eq

Now we have to calculate the molecular mass of polymer.

As, the mass of polymer of 7.02\times 10^{18} molecules = 1.22 mg = 0.00122 g

So, the mass of polymer of 6.022\times 10^{23} molecules = \frac{6.022\times 10^{23}}{7.02\times 10^{18}}\times 0.00122g=104.6g/mol

Now we have to calculate the molecular formula of the compound.

Formula used :

n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}

n=\frac{104.6}{13}=8

Molecular formula = (C_1H_1)_n=(C_1H_1)_8=C_8H_8

Therefore, the molecular of the compound is, C_8H_8

5 0
3 years ago
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