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3 years ago

Please help me do this question

Chemistry

2 answers:

Delicious77 [7]3 years ago

7 0

How many pages is 5000 words? Double spaced, 5000 words is around 20 pages; single spaced about 10 pages. Now, if you're using an unconventional formatting or margins you could see different results, however, with standard word processor defaults and a 12 point Arial or Times New Roman font your output should be very similar. Examples of 5000 word count pages include college theses, dissertation research, or very comprehensive, in-depth blog posts.

Answer: 5000 words is 10 pages single spaced or 20 pages double spaced.

Pages by Word Count

Use our handy table to discover how many pages a given word count yields, single or double spaced, in Times New Roman or Arial 12 point font.

Word Count Pages (single spaced) Pages (double spaced) Font Size

250 WORDS ½ PAGE 1 PAGE 12 POINT

300 WORDS ⅔ PAGE 1⅓ PAGES 12 POINT

400 WORDS ⅘ PAGE 1⅗ PAGES 12 POINT

500 WORDS 1 PAGE 2 PAGES 12 POINT

600 WORDS 1⅓ PAGE 2⅔ PAGES 12 POINT

750 WORDS 1½ PAGES 3 PAGES 12 POINT

800 WORDS 1⅗ PAGES 3⅕ PAGES 12 POINT

1000 WORDS 2 PAGES 4 PAGES 12 POINT

1200 WORDS 2⅖ PAGES 4⅘ PAGES 12 POINT

1500 WORDS 3 PAGES 6 PAGES 12 POINT

2000 WORDS 4 PAGES 8 PAGES 12 POINT

2500 WORDS 5 PAGES 10 PAGES 12 POINT

3000 WORDS 6 PAGES 12 PAGES 12 POINT

3500 WORDS 7 PAGES 14 PAGES 12 POINT

4000 WORDS 8 PAGES 16 PAGES 12 POINT

5000 WORDS 10 PAGES 20 PAGES 12 POINT

6000 WORDS 12 PAGES 24 PAGES 12 POINT

7500 WORDS 15 PAGES 30 PAGES 12 POINT

8000 WORDS 16 PAGES 32 PAGES 12 POINT

10000 WORDS 20 PAGES 40 PAGES 12 POINT

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RELATED

How Many Pages is 4000 Words?

How many pages does 4000 words equal? Single spaced, 4000 words would produce about 8 pages; double spaced around 16 pages.

How Many Pages is 300 Words?

How many pages is 300 words? The answer is close to two-thirds of a page single spaced, and around one and one-third of a page double spaced.

How Many Pages is 400 Words?

How many pages does 400 words take? A word count of 400 words will result in around four-fifths of a page single spaced and and one and three-fifths of a page double spaced.

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Advocard [28]3 years ago

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Question 2 (1 point)<br>At the center of the atom is the electron.<br>True<br>False

Stells [14]

Answer:

False the electrons are on the outside of the atoms

Explanation:

5 0

3 years ago

A tank at is filled with of chlorine pentafluoride gas and of sulfur hexafluoride gas. You can assume both gases behave as ideal

Ivan

Answer:

- Mole fraction of Chlorine Pentafluoride

= 0.265

- Partial Pressure of Chlorine Pentafluoride

= 16.05 kPa

- Mole fraction of Sulfur Hexafluoride

= 0.735

- Partial Pressure of Sulfur Hexafluoride

= 44.53 kPa

Total Pressure exerted by the gases = 60.58 kPa

Explanation:

First of, we calculate the number of moles of each gas present.

Number of moles = (Mass)/(Molar Mass)

For ClF₅

Mass = 4.28 g

Molar Mass = 130.445 g/mol

number of moles of Chlorine Pentafluoride

= (4.28/130.445) = 0.0328 moles

For SF₆

Mass = 13.3 g

Molar Mass = 146.06 g/mol

number of moles of Sulfur Hexafluoride

= (13.3/146.06) = 0.0911 moles

Total number of moles present = 0.0328 + 0.0911 = 0.1239 moles.

Using the ideal gas equation

PV = nRT

P = total pressure in the tank = ?

V = volume of the tank = 5.00 L = 0.005 m³

R = molar gas constant = 8.314 J/mol.K

T = temperature of the tank = 20.9°C = 294.05 K

n = total number of moles present = 0.1239 moles

P × 0.005 = (0.1239 × 8.314 × 294.05)

P = 60,580.45 Pa = 60.58 kPa.

- Mole fraction of a particular component of interest = (number of moles of the component of interest) ÷ (total number of moles)

- Partial Pressure of a particular component of interest = (mole fraction of that component of interest) × (total pressure)

This is Dalton's law of Partial Pressure.

- Mole fraction of Chlorine Pentafluoride

= (0.0328/0.1239) = 0.265

- Partial Pressure of Chlorine Pentafluoride

= 0.265 × 60.58 = 16.05 kPa

- Mole fraction of Sulfur Hexafluoride

= (0.0911/0.1239) = 0.735

- Partial Pressure of Sulfur Hexafluoride

= 0.735 × 60.58 = 44.53 kPa

Total Pressure exerted by the gases = 16.04 + 44.53 = 60.58 kPa

Hope this Helps!!!

3 0

3 years ago

10mL volume of 75mM EtOH is necessary for an experiment. What volumes of 1M EtOH and water should be mixed to obtain the working

kenny6666 [7]

Answer: Volume of the 1M EtOH and water should be 0.75 ml and 9.25 ml respectively to obtain the working concentration.

Explanation:

According to the dilution law,

$C_1V_1=C_2V_2$

where,

$C_1$ = molarity of stock solution = 1M

$V_1$ = volume of stock solution = ?

$C_2$ = molarity of diluted solution = 0.075 M (1mM=0.001M)

$V_2$ = volume of diluted solution = 10 ml

Putting in the values we get:

$1M\times V_1=0.075M\times 10ml$

$V_1=0.75ml$

Thus 0.75 ml of 1M EtOH is taken and (10-0.75)ml = 9.25 ml of water is added to make the volume 10ml.

Therefore, volume of the 1M EtOH and water should be 0.75 ml and 9.25 ml respectively to obtain the working concentration

3 0

3 years ago

A flame is the result of a chemical reaction that releases energy. Do you think a similar kind of chemical reaction is happening

almond37 [142]

Answer:

Chemical reactions that take place inside living things are called biochemical reactions. Explanation:The sum of all the biochemical reactions in an organism is referred to as metabolism. Metabolism includes both exothermic (heat-releasing) chemical reactions and endothermic (heat-absorbing) chemical reactions.

4 0

2 years ago

In the modern periodic table when elements are arranged according to their atomic

9966 [12]

In the modern periodic table when elements are arranged according to their atomic number.

3 0

3 years ago