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ioda
3 years ago
14

Chlorine can be prepared in the laboratory by the reaction of manganese dioxide with hydrochloric acid, HCl(aq), as

Chemistry
1 answer:
zubka84 [21]3 years ago
6 0

Answer:

Explanation:

MnO₂(s) + 4 HCl(aq)  = MnCl₂(aq) + 2 H₂O(l) + Cl₂

87 g                                                                     22.4 x 10³ mL

volume of given chlorine gas at NTP or at 760 Torr and 273 K

=  175 x ( 273 + 25 ) x 715 / (273 x 760 )

= 179.71 mL

22.4 x 10³ mL of chlorine requires 87 g of MnO₂

179.4 mL of chlorine will require    87 x 179.4 / 22.4 x 10³ g

= 696.77 x 10⁻³ g

= 696.77 mg .

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What type of organism might contain this type of cell
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is there supposed be a picture with the question?


3 0
3 years ago
8. A party-supply store sells a helium-gas
MatroZZZ [7]

Answer:

P₂= 116.7 atm

Explanation:

Here apply the Boyle's law equations that states :at constant temperature the volume of a dry mass of a gas is inversely proportional to its pressure.

This is simplified as;

P₁V₁=P₂V₂ where P is pressure and V is volume

Given that;

P₁=1

V₁=1.81 m³

P₂=?

V₂=1.55*10^-2 m³

Apply the formula

1*1.81 =P₂*1.55*10^-2 m³

1.81/1.55*10^-2  =P₂

P₂= 116.7 atm

7 0
2 years ago
Which 2 elements when combined NOT alloys?
Volgvan

Answer:

Oxygen and sulfur

Explanation:

Alloys consist of metals fused together sometimes with additional components, such as carbon, to prevent metals from corrosion.

Oxygen and sulfur are two compounds consisting of non-metal atoms, O and S. Combining oxygen with sulfur would actually produce sulfur dioxide, a gas, in contrast to a metallic substance that is fused with some other metal or carbon.

That's the reason why combination of sulfur and oxygen wouldn't produce an alloy: it would produce a gas.

6 0
3 years ago
What is the overall enthalpy of reaction for the equation shown below?
Rudiy27

Answer:

ΔH₁₂ = -867.2 Kj

Explanation:

Find enthalpy for 3H₂ + O₃ => 3H₂O given ...

2H₂ + O₂ => 2H₂O      ΔH₁ = -483.6 Kj

        3O₂ => 2O₃        ΔH₂ = + 284.6 Kj

_____________________________

3(2H₂ + O₂ => 2H₂O) => 6H₂ + 3O₂ => 6H₂O       (multiply by 3 to cancel O₂)

6H₂ + 3O₂ => 6H₂O        ΔH₁ = 3(-483.6 Kj) = -1450.6Kj

          2O₃ => 3O₂           ΔH₂ = -284.6Kj              (reverse rxn to cancel O₂)

_______________________________

6H₂ + 2O₃ => 6H₂O         ΔH₁₂ = -1735.2 Kj       (Net Reaction - not reduced)

________________________________

divide by 2 => target equation (Net Reaction - reduced)

3H₂ + O₃ => 3H₂O            ΔH₁₂ = (-1735.2/2) Kj = -867.2 Kj    

4 0
3 years ago
Populations have some genetic {blank}
Juliette [100K]
<h3>✽ - - - - - - - - - - - - - - -  ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ Populations have some genetic variation.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

4 0
3 years ago
Read 2 more answers
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