Answer:
mark me
Step-by-step explanation:
x+y=3
x=3-y
putting the value of x
in this
x²+y²=5
(3-y) ²+y²=5
9-6y+y²+y²=5
2y²-6y+9-5=0
2y²-6y+4=0
2y²-4y-2y+4=0
2y(y-2)-2(y-2)=0
(2y-2) (y-2) =0
2y-2=0 or y-2=0
y=1 or y=2
so x=2 or 1
so x×y=2×1 or 1×2=2
I HOPE THIS WILL HELP YOU MARK ME BRAINLIEST
<span>The value 28 should have been rounded to 2×101
</span>
Answer31 i don't know :(
Step-by-step explanation:
Look at the attachment
The line bisects the cord which we have to find
- Length of chord=12cm
- Half of the cord=12/2=6cm
- Radius=10cm
Its a right angle triangle
- using Pythagorean theorem






Distance of the chord from centre is 8cm.