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Gwar [14]
1 year ago
12

If a 1.0x10-5 L sample of agas at 2.0x106 atm isreleased until it is equal to0.275 atm, what would thenew volume of the gas be?

Chemistry
1 answer:
Greeley [361]1 year ago
5 0

Answer:

Explanation:

Here, we want to get the new volume of the gas

What we need to know is the law that connects volume and pressure at constant temperature

The law that supports this is the Boyle's law

It states that the volume of a given mass of gas is inversely proportional to its pressure at constant temperature

Mathematically, we can have this as represented as:

\begin{gathered} P_1V_1=P_2V_2 \\ P_1\text{ = 2.0 }\times10^{6\text{ }}\text{ atm} \\ V_1\text{ = 1.0 }\times10^{-5}\text{ L} \\ P_2\text{ =0.275 atm} \\ V_2\text{ = ?} \end{gathered}

We can proceed mathematically to solve as follows;

undefined

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A quantum of light has frequency of 1.8 x 10^14 Hz. Finds its energy.
SVETLANKA909090 [29]

Its energy : 1.193 x 10⁻¹⁹ J

<h3>Further explanation </h3>

Radiation energy is absorbed by photons

The energy in one photon can be formulated as

\large{\boxed{\bold{E\:=\:h\:.\:f}}}

Where

h = Planck's constant (6,626.10⁻³⁴ Js)

f = Frequency of electromagnetic waves

f = c / λ

c = speed of light

= 3.10⁸

λ = wavelength

\tt E=6.626\times 10^{-34}\times 1.8\times 10^{14}\\\\E=1.193\times 10^{-19}~J

3 0
3 years ago
A compound with the empirical formula NPCl2 was found in a subsequent experiment to have a molar mass of 347.64 g/mol. What is t
Irina-Kira [14]

Answer:

                     Molecular Formula  =  N₃P₃Cl₆

Explanation:

Molecular formula is calculated by using following formula,

                    Molecular Formula  =  n × Empirical Formula  ---- (1)

Also, n is given as,

                     n  =  Molecular Weight / Empirical Formula Weight

Molecular Weight  =  347.64 g.mol⁻¹

Empirical Formula Weight  =  1 (N) + 1 (P) + 2 (Cl)  =  115.88 g.mol⁻¹

So,

                     n  =  347.64 g.mol⁻¹ ÷ 115.88 g.mol⁻¹

                     n  =  3

Putting Empirical Formula and value of "n" in equation 1,

                    Molecular Formula  = 3 × NPCl₂

                    Molecular Formula  =  N₃P₃Cl₆

7 0
3 years ago
What are the two products in complete combustion reactions?
JulsSmile [24]

Answer: Combustion is also known as burning, and the substance that burns is usually referred to fuel.  The products of a complete combustion reaction include carbon dioxide (CO2) and water vapor (H2O).

Explanation:

8 0
3 years ago
Read 2 more answers
A sample of N2(g) was collected over water at 25°C and 730 torr in a container with a volume of 340 mL. The vapor pressure of wa
AnnZ [28]

Answer:

D. 0.36 g

Explanation:

When a gas is collected over water, the total pressure is the sum of the pressure of the gas and the pressure of the water vapor.

Ptotal = Pwater + PN₂

PN₂ = Ptotal - Pwater = 730 torr - 23.76 torr = 706 torr

We can find the mass of N₂ using the ideal gas equation.

P.V=n.R.T=\frac{m}{M} .R.T\\m=\frac{P.V.M}{R.T} =\frac{730torr.0.340L.28g/mol}{(0.08206atm.L/mol.K).298K} .\frac{1atm}{760torr} =0.36g

6 0
3 years ago
How many grams of o2 are in a 5.0 mol of the oxygen gas?
allsm [11]
We are tasked to find the amount of O2 in grams given only the number of moles of oxygen gas. To solve the problem, we need first to calculate the molecular weight of oxygen. Based on the periodic table, elemental oxygen has a molecular weight of 16 g/mol. Thus its molecular weight is,
O2=16.0g/mol (2)=32 g/mol

To solve for the amount of compound oxygen in grams, we have,
O2 (g)=5 mol x 32 g/mol =160 g.

This cancel out the mols both in the numerator and denominator leaving only the g as a unit. Therefore, 5 mols of oxygen is equal to 160 g of oxygen.
4 0
3 years ago
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