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Answer:
1. 44.11 g
2. 36.03 g
3. 8.08 g
4. 81.7%
5. 18.3%
Explanation:
1. 12.01+12.01+12.01+1.01+1.01+1.01+1.01+1.01+1.01+1.01+1.01=44.11
2. 12.01×3= 36.03
3. 1.01×8= 8.08
4.(36.03/44.11)×100= 81.7%
5. (8.08/44.11)×100= 18.3%
Answer:
3.62moles
Explanation:
First let us generate a balanced equation for the reaction
2Na + Cl2 —> 2NaCl
Molar Mass of Na = 23g/mol
Mass of Na from the balanced equation = 2 x 23 = 46g
Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol
Mass of NaCl from the balanced equation = 2 x 58.5 = 117g
From the question,
46g of Na produced 117g of NaCl.
Therefore, 83g of Na will produce = (83 x 117)/46 = 211.11g of NaCl
Converting this mass (211.11g of NaCl) to mole, we obtain:
n = Mass /Molar Mass
n = 211.11/ 58.5
3.62moles
Answer:
1. 0.02 M
2. 0.01 M
3. 4×10⁻⁶
Explanation:
We know that V₁S₁ = V₂S₂
1.
Concentration of HCl = 0.05 M
end point comes at = 10 ml
So, concentration of OH⁻(aq) = [OH⁻(aq)] ⇒ (0.05 × 10) ÷ 25 ⇒ 0.02 M
2.
2mol of OH⁻(aq) ≡ 1 mole of Ca²⁺(aq)
[Ca²⁺] = 0.02 ÷ 2 = 0.01 M
3.
= [Ca²⁺(aq)] [OH⁻(aq)]²
Ca(OH)₂ (aq) ⇄ Ca²⁺ (aq) + 2OH⁻ (aq)
= [0.01 × (0.02)²] = 4×10⁻⁶
4.
If reaction is exothermic which means heat energy will get evolved as a result temperature of the reaction media will get increased during the course of the reaction. If temperature is externally increased, the reaction will go backward to accumulate extra heat energy.
5.
value describes the solubility of a particular ionic compound. The higher the
value, the higher the Solubility will be.
6.
This may be due to uncommon ion effect. The process of other ions (K⁺ or Na⁺) may increase the solubility
he is a good scientist because he postulated that chemical reactions resulted in the rearrangement of the reacting atoms