Answer:
a. KCl, c. BaCl2 and e. LiF.
Explanation:
Hello,
In this case, we can identify the ionic compounds by verifying the difference in the electronegativity between the bonding compounds when it is 1.7 or more (otherwise it is covalent) as shown below:
a. KCl: 3.0-0.9=2.1 -> Ionic.
b. C2H4: 2.5-2.1=0.4 -> Covalent.
c. BaCl2: 3.0-0.8=2.2 -> Ionic.
d. SiCl4: 3.0-1.8=1.2 -> Covalent.
e. LiF: 4.0-1.0=3.0 -> Ionic.
Therefore, ionic compounds are a. KCl, c. BaCl2 and e. LiF.
Regards.
No math is needed to explain this. All that you need to know is that the can (4°C) is in your hand (37°C).
Entropy will always move toward being balanced. Never will you find a lake in which half of it is 1°C and the other half is 70°C; it will be equal throughout.
Remember that "cold" doesn't exist. What we describe to be cold is actually a lack of heat.
So, by applying the two ideas above, it can be concluded that:
Since your hand is warmer than the can, the heat from your hand will be transferred to the can in order to reach an equal temperature.
Answer:
- <em>The addition of a small amount of HCl to a solution containing fluoride ions and hydrogen fluoride</em> <u>will cause the equilibrium shift to the production of more hydrogen fluoride.</u>
Explanation:
The solution containing <em>fluoride ions and hydrogen fluoride</em> (a weak acid) may be chemically represented by this equilibrium equation:
- F⁻ (aq) + H⁺ (aq) ⇄ HF (aq)
The <em>HCl</em>, a strong acid, added will ionize in water according to this chemical equation:
- HCl (aq) → H⁺ (aq) + Cl⁻ (aq)
Then, following Le Chatelir's principle, the addtion of H⁺ ions coming from the HCl dissociation, will increase the concentration of H⁺ in the solution, driving to the consumption of some F⁻ ions, and the production of more HF acid. This is a shift of the equilbrium toward the HF side.
The spacing is 14.4 nm (nanometers).
It is 14.4 * 10^(-9) m
And 1 mm = 1 * 10^(-3) m
14.4 nm * 105 = 1,512 nm = 1.512 micrometers = 0.001512 mm
Or : 1.512 * 10^(-3) mm
Answer: The total width of crystal is 0.001512 mm.
Answer: CF4
Explanation:
Calculate the molar mass of each compound. Divide the molar mass of Carbon by the molar mass of each compound, then multiply the answer by 100 to get the percentage.
CF4= 12+(19X 4)
=12+76= 88 g/mol
%C= 12/88 x 100= 13.64%
CO2= 12+(16 X 2)
12+32= 44 G/MOL
%C= 12/44 x 100= 27.3%
CH4= 12+ (1 X4)
=12+4
=16 G/MOL
%C= 12/16 X 100= 75%
C204
(12X2) + (16X4)
24+64
= 88 g/mol
%C= 24/88 x 100
= 27.3%
