<span>To determine the pH of the solution given, we make
use of the acid equilibrium constant (Ka) given. It is the ratio of the
equilibrium concentrations of the dissociated ions and the acid. The
dissociation reaction of the CH3COOH acid would be as follows:
</span>CH3COOH = CH3COO- + H+<span>
The acid equilibrum constant would be expressed as follows:
Ka = [H+][</span>CH3COO-] / [CH3COOH] = 1.8× 10^–5
<span>
To determine the equilibrium concentrations we use the ICE table,
CH3COOH H+ </span>CH3COO<span>-
I 1.60 0 0
C -x +x +x
----------------------------------------------------------------
E 1.60-x x x
</span>1.8× 10^–5 = [H+][CH3COO-] / [CH3COOH] <span>
1.8 x 10^-5 = [x][x] / [0.160-x] </span>
Solving for x,
x = 1.69x10^-3 = [H+] = [F-]
pH = -log [H+] = -log [1.69x10^-3] = 2.8
Group 1a elements (the first column on the left side of the Periodic table) always release one electron to form positive ions with a charge of +1. Group 7a nonmetals (the <em>second to the last </em>column on the right side- the rightmost column are the noble gases) always desire to gain one electron to form negative ions with a charge of -1.
Since their charges are equal and opposite, they will always combine in a 1:1 ratio.
T½=18.72days
therefore t¾=18.72+½ of 18.72
we have 18.72+9.36=28.08days
