How many inches are in 1 meter?

What are the coefficients in the polynomial 4x2 + 3x-3?

Ksenya-84 [330]

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What are the coefficients in the polynomial 4x²+3x-3?

$\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to solve:-}}}}\diamond$

Coefficient:- A number before a variable

Coefficients in this polynomial:-

4 (the number before x²) and 3 (the number before x)

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So we conclude that the right option is:-

$\bigcirc\!\!\!\!\!\large\checkmark$ 4, 3 (Option B)

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4 0

2 years ago

What is an outlier in math?

Flura [38]

A outlier is something spread out from the rest for example you have the numbers 12, 9, 3,10, 16, 89 obviously the outlier is 89 so the number spread from the rest

7 0

3 years ago

Read 2 more answers

Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

Step(i):-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

Step(ii):-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

Step(iii):-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

Final answer:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

3 0

3 years ago

The diagonal length of a rectangle is 25 inches, and the length of the rectangle is 9 inches.

diamong [38]

Answer:

Option C is the right answer.

Step-by-step explanation:

Given that:

Length of diagonal = 25 inches

Length of rectangle = 9 inches

Width of rectangle will be one of the two legs of right angled triangle and the diagonal will be the hypotenuse.

Using Pythagorean theorem;

$a^2+b^2=c^2\\(9)^2+w^2=(25)^2\\81 + w^2 = 625 \\w^2 = 625-81\\w^2 = 544$

Taking square root;

$\sqrt{w^2}=\sqrt{544}\\w=23.3$

Therefore,

Option C is the right answer.

3 0

3 years ago

This is math please help !!!!!!!

aev [14]

Answer:

Hello I'lll solve this problem.

Step-by-step explanation:

So the answer is actually C. I did the work.

3 0

3 years ago