Answer:

Step-by-step explanation:
Given:
A car starts with a dull tank of gas
1/7 of the gas has been used around the city.
With the rest of the gas in the car, the car can travel to and from Ottawa three times.
Question asked:
What fractions of a tank of gas does each complete trip to Ottawa use?
Solution:
Fuel used around the city = 
Remaining fuel after driving around the city = 1 -
= 
According to question:
As from the rest of the gas in the car that is
, the car can complete 3 trip to Ottawa which means,
By unitary method:
The car can complete 3 trip by using =
tank of gas.
The car can complete 1 trip by using = 
=
= 
=
tank of gas
Thus,
tank of gas used for each complete trip to Ottawa.
Answer:
Sabemos que:
L es el largo de la avenida.
En la primer etapa se asfalto la mitad, L/2, entonces lo que queda por asfaltar es:
L - L/2 = L/2.
En la segunda etapa se asfalto la quinta parte, L/5, entonces lo que queda por asfaltar es:
L/2 - L/5 = 5*L/10 - 2*L/10 = (3/10)*L
En la tercer etapa se asfalto la cuarta parte del total, L/4, entonces lo que queda por asfaltar es:
(3/10)*L - L/4 = 12*L/40 - 10L/40 = (2/40)*L
Y sabemos que este ultimo pedazo que queda por asfaltar es de 200m:
(2/40)*L = 200m
L = 200m*(40/2) = 4,000m