Answer:
distance difference would a) increase
speed difference would f) stay the same
Explanation:
Let t be the time the 2nd skydiver takes to travel, since the first skydiver jumped first, his time would be t + Δt where Δt represent the duration between the the first skydiver and the 2nd one. Remember that as t progress (increases), Δt remain constant.
Their equations of motion for distance and velocities are
Their difference in distance are therefore:
(As
So as time progress t increases, Δs would also increases, their distance becomes wider with time.
Similarly for their velocity difference
Since g and Δt both are constant, Δv would also remain constant, their difference in velocity remain the same.
This of this in this way: only the DIFFERENCE in speed stay the same, their own individual speed increases at same rate (due to same acceleration g). But the first skydiver is already at a faster speed (because he jumped first) when the 2nd one jumps. The 1st one would travel more distance compare to the 2nd one in a unit of time.
Answer:
10.31 m
Explanation:
To find the result you have to use the formula: h = p / eg.
Where: e = 1000Kg/m^3 g=9.8m/s^2 p= 1.01 * 10^5 Pa
The calculation will be:
h= 1.01 * 10^5 / (1000kg/m^2) * (9.8m/s^2)
h= 10.31 m
In sulfur dioxide, there are 2 oxygen atoms and 1 sulfur atom. As there are 32g of sulfur and 32g of oxygen, that would mean that each oxygen atom would weigh about 16g. Given that, the mass of a single sulfur atom is twice that of a single oxygen atom.
The force of gravity increases with mass, but decreases with increasing distance between objects.