The boiling point of water is 100°C. So at 101°C, the water is steam. Compute the specific heat first from 101 to 100.
E = mCΔT, where c for steam is 1.996 kJ/kg·°C
E₁ = (0.65 kg)(1.996 kJ/kg·°C)(101 - 100°C) = 1.2974 kJ
Next, let's solve the latent heat when steam turns to liquid. The heat of vaporization of water is 2260 kJ/kg.
E₂ = mHvap = (0.65 kg)(2260 kJ/kg) = 1469 kJ
Lastly, let's solve the energy to bring down the temperature to 51°C. The specific heat of liquid water is 4.187 kJ/kg·°C.
E₃ = (0.65 kg)(4.187 kJ/kg·°C)(100 - 51°C) = 139.36 kJ
Thus,
<em>Total energy = 1.2974 kJ+1469 kJ+139.36 kJ = 1,609.66 kJ</em>
Temperature will rise until reaching 0°C.
<span>One leg is = 12 m, and the other leg is 16 m. </span>
C. inertia. the man is sent flying off the bus because of his weight and the sudden stop of the bus. this effect is called inertia. an example of gravity would be throwing an apple up and having it come to the ground. an example of weight would be putting a man and an elephant on a scale and having the elephant come down while the man goes up.
