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3 years ago

An airplane propeller is rotating at 1900 rpm (rev/min).

Physics

1 answer:

alexandr1967 [171]3 years ago

3 0

Answer:

See explanation

Explanation:

We have to convert to angular velocity in rads-1 as follows;

Angular velocity in rad/s = 2π/60 × 1900 rpm = 199 rad/s

Given that

angular velocity =angle turned /time taken

Time taken = angle turned/angular velocity

Converting 35° to radians we have;

35 × π/180 = 0.61 radians

Time taken = 0.61 radians/199 rad/s

Time taken = 0.0031 seconds

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Three batteries are connected in series so that the total voltage is 54 volts. The voltage of the first battery is twice the vol

Alex_Xolod [135]

Answer:

$v_1 = 12 volts$

$v_2 = 6 volts$

$v_3 = 36 volts$

Explanation:

As we know that all the batteries are in series

so the net voltage of all three batteries is given as

$V = v_1 + v_2 + v_3$

now we know that

$v_1 = 2v_2$

$v_1 = \frac{1}{3}v_3$

now plug in all the values in it

$54 = v_1 + \frac{v_1}{2} + 3v_1$

$54 = 4.5 v_1$

$v_1 = 12 volts$

now we have

$v_2 = 6 volts$

$v_3 = 36 volts$

3 0

3 years ago

A parallel-plate vacuum capacitor has 8.38 J of energy stored in it. The separation between the plates is 2.30 mm. If the separa

Elanso [62]

Answer:

Explanation:

plate separation = 2.3 x 10⁻³ m

capacity C₁ = ε A / d

= ε A / 2.3 x 10⁻³

C₂ = ε A / 1.15 x 10⁻³

$\frac{C_2}{C_1}$ = $\frac{2.3}{1.15}$

a ) when charge remains constant

energy = $\frac{q^2}{2C}$

q is charge and C is capacity

energy stored initially E₁= $\frac{q^2}{2C_1}$

energy stored finally E₂ = $\frac{q^2}{2C_2}$

$\frac{E_1}{E_2} = \frac{C_2}{C_1}$ = $\frac{2.3}{1.15}$

$E_2$ = $\frac{1.15}{2.3 } \times E_1$

= $\frac{1.15}{2.3 } \times 8.38$

= 4.19 J

b )

In this case potential diff remains constant

energy of capacitor = 1/2 C V²

energy is proportional to capacity as V is constant .

$\frac{E_2}{E_1} = \frac{C_2}{C_1}$

$\frac{E_2}{8.38} = \frac{2.3}{1.15}$

$E_2$ = 16.76 .

8 0

3 years ago

The perihelion of the comet TOTAS is 1.69 AU and the aphelion is 4.40 AU. Given that its speed at perihelion is 28 km/s, what is

dybincka [34]

Answer:

The speed at the aphelion is 10.75 km/s.

Explanation:

The angular momentum is defined as:

$L = mrv$ (1)

Since there is no torque acting on the system, it can be expressed in the following way:

$t = \frac{\Delta L}{\Delta t}$

$t \Delta t = \Delta L$

$\Delta L = 0$

$L_{a} - L_{p} = 0$

$L_{a} = L_{p}$ (2)

Replacing equation 1 in equation 2 it is gotten:

$mr_{a}v_{a} =mr_{p}v_{p}$ (3)

Where m is the mass of the comet, $r_{a}$ is the orbital radius at the aphelion, $v_{a}$ is the speed at the aphelion, $r_{p}$ is the orbital radius at the perihelion and $v_{p}$ is the speed at the perihelion.

From equation 3 v_{a} will be isolated:

$v_{a} = \frac{mr_{p}v_{p}}{mr_{a}}$

$v_{a} = \frac{r_{p}v_{p}}{r_{a}}$ (4)

Before replacing all the values in equation 4 it is necessary to express the orbital radius for the perihelion and the aphelion from AU (astronomical units) to meters, and then from meters to kilometers:

$r_{p} = 1.69 AU x \frac{1.496x10^{11} m}{1 AU}$ ⇒ $2.528x10^{11} m$

$r_{p} = 2.528x10^{11} m x \frac{1km}{1000m}$ ⇒ $252800000 km$

$r_{a} = 4.40 AU x \frac{1.496x10^{11} m}{1 AU}$ ⇒ $6.582x10^{11} m$

$r_{p} = 6.582x10^{11} m x \frac{1km}{1000m}$ ⇒ $658200000 km$

Then, finally equation 4 can be used:

$v_{a} = \frac{(252800000 km)(28 km/s)}{(658200000 km)}$

$v_{a} = 10.75 km/s$

Hence, the speed at the aphelion is 10.75 km/s.

8 0

3 years ago

On June 21, the sun never sets at John's location. Based on this, it can be concluded that John lives:

Lesechka [4]

It can be concluded that John lives at the Arctic Circle.

<h3></h3><h3>Why sun don't sets at arctic circle?</h3>

The North Pole is inclined toward our star throughout the summer because of the slanted axis of the earth's rotation with respect to the sun. Because of this, the sun never sets over the Arctic Circle for a few weeks.

Norway. Norway, which is located in the Arctic Circle, is known as the Land of the Midnight Sun because there the sun never sets from May until late July. This implies that the sun doesn't set for around 76 days.

to learn more about arctic circle go to -

brainly.com/question/10306896

#SPJ4

4 0

2 years ago

A drag racer crosses the finish line doing 212 mi/h and promptly deploys her drag chute. (A.) what force must the drag chute exe

Svet_ta [14]

initial speed of the racer is given as

$v_i = 212 mi/h$