Answer:
- 45 regular keyboards
- 15 wireless keyboards
Step-by-step explanation:
A set of 3 regular and 1 wireless keyboard would sell for ...
3×$83 +110 = $359
For the given sales, the number of sets sold was ...
$5385/($359/set) = 15 sets
Since there are 3 regular keyboards in each set, there were 3×15 = 45 regular keyboards sold. The number of each type of keyboards sold is ...
45 regular keyboards and 15 wireless keyboards
_____
<em>Comment on this solution</em>
When a problem statement tells you the ratio of one kind of item to another, it is often convenient to group the items in that ratio and deal with the groups. Sometimes, there will be a few missing or left over, for example "10 more than 3 times as many." In those cases, you can make an adjustment to the total and still deal with the groups. (Any equations you might write will effectively do this same thing.)
Answer:
1 and the 3rd
Step-by-step explanation:
Answer:
Step-by-step explanation:
A well defined set is one which is universally defined and accepted, you can easily define what the set is and what is not a member of the set.example is a set of integers between 1 and 30
A not well defined set is one which is ill defined set. example is a list of hit musical hit of 2019
Answer:
56
Step-by-step explanation:
(14-7) x (40-32) = 7 x 8
= 56
Hope you understood :)
X=2h, y=3k
Substitute these values into equations.
y+2x = 4 ------> 3k+2*2h=4 -----> 3k +4h =4
2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1
We have a system of equations now.
3k +4h =4 ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1
2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0
4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0
(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0
Denominator cannot be = 0
4h(2-2h)≠0
Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4 or h=-1
Check which
4h(2-2h)≠0
1) h= 3/4 , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.
h=3/4, then 3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then 3k = 4-4*(-1) =8 , 3k=8, k=8/3
So,
if h=3/4, then k=1/3,
and if h=-1, then k=8/3 .
