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laiz [17]
3 years ago
15

A 2x6 rectangle has the same perimeter as a square of area A) 4 B) 12 C) 16 D) 144

Mathematics
1 answer:
Nataly [62]3 years ago
5 0
Answer: C) 16

We know that the x or y axis side is 2 and 6
If we double the number to find the perimeter:
2 - 4
6 - 12
—-
16
Therefore the answer is 16
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If bacteria took 20 minutes to double from 2 to 4, how many bacteria would there be after 1 hour
iren2701 [21]
4 * 2 * 2 * 2 = 32 bacteria

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3 0
3 years ago
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In the following isosceles trapezoid, find the value of x.
yulyashka [42]

Answer:

24

Step-by-step explanation:

22 - 8 = 14

14/2 = 7

Pythagoras theorem

25 squared -7 squared = 576

square root of 576 = 24

5 0
3 years ago
Eli invested $ 330 $330 in an account in the year 1999, and the value has been growing exponentially at a constant rate. The val
Cloud [144]

Answer:

The value of the account in the year 2009 will be $682.

Step-by-step explanation:

The acount's balance, in t years after 1999, can be modeled by the following equation.

A(t) = Pe^{rt}

In which A(t) is the amount after t years, P is the initial money deposited, and r is the rate of interest.

$330 in an account in the year 1999

This means that P = 330

$590 in the year 2007

2007 is 8 years after 1999, so P(8) = 590.

We use this to find r.

A(t) = Pe^{rt}

590 = 330e^{8r}

e^{8r} = \frac{590}{330}

e^{8r} = 1.79

Applying ln to both sides:

\ln{e^{8r}} = \ln{1.79}

8r = \ln{1.79}

r = \frac{\ln{1.79}}{8}

r = 0.0726

Determine the value of the account, to the nearest dollar, in the year 2009.

2009 is 10 years after 1999, so this is A(10).

A(t) = 330e^{0.0726t}

A(10) = 330e^{0.0726*10} = 682

The value of the account in the year 2009 will be $682.

4 0
4 years ago
Eric surveys students at his school and finds that 80% have a pet. He wants to estimate the probability that, if he randomly sel
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Yes that is correct what is the question
7 0
3 years ago
Change the following mixed number to an improper fraction. Reduce if possible. 2 4/40
slava [35]
84/40

Reduces to 21/10
4 0
3 years ago
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