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sammy [17]
3 years ago
8

If earth did not rotate what would happen to the global winds and why?

Chemistry
2 answers:
Anna35 [415]3 years ago
3 0
If earth didn't rotate the global winds would stay on the same speed of rate because the wind isn't moving without rotation in the earths axis.
Nonamiya [84]3 years ago
3 0
     <span> A non-stop 200 mph wind would occur between day and night</span>
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Determine the change in volume that takes place when a 2.00 L sample of N2 gas is heated from 250 C to 500 C.
Effectus [21]

Answer:

V₂ = 2.96 L

Explanation:

Given data:

Initial volume = 2.00 L

Initial temperature =  250°C

Final volume = ?

Final temperature = 500°C

Solution:

First of all we will convert the temperature into kelvin.

250+273 = 523 k

500+273= 773 k

According to Charles's law,

V∝ T

V = KT

V₁/T₁ = V₂/T₂

V₂ = T₂V₁/T₁

V₂ = 2 L × 773 K / 523 k

V₂ =  1546 L.K / 523 k

V₂ = 2.96 L

4 0
3 years ago
When writing a formula for a compound having a transition metal in it, _____.
Stella [2.4K]

Answer:

it is always necessary to use the roman numeral as the assigned charge of the metal.

Explanation:

This is so that one would know which Transition metal is being used. For example copper (II) would be Cu²+

3 0
3 years ago
There are four substances, A, B C and D. A and C are pure substances. They cannot be broken down into anything simpler by chemic
yarga [219]

The answer is C Becuz D is a compound and that is the only answer that says it

6 0
3 years ago
The energy of a photon is ________ proportional to its wavelength. The energy of a photon is ________ proportional to its freque
topjm [15]

Answer: Inversely  ,   Directly

Explanation:

The energy of a photon is inversely proportional to its wavelength and directly proportional to its frequency.

As can be seen from this equation;

E = hv  = h c / ∧

Where E = Energy of a photon

           v = Frequency

           h = Planck Constant

           c = speed of light

           ∧  = Wave length

4 0
3 years ago
A mixture of gases has 0.3000 mol of CO2, 0.2706 mol of SO2 and 0.3500 mol of water vapor. The total pressure of the mixture is
notka56 [123]

Answer:

Partial pressure SO₂ → 0.440 atm

Explanation:

We apply the mole fraction concept to solve this:

Moles of gas / Total moles = Partial pressure of the gas / Total pressure

Total moles = 0.3 moles of CO₂ + 0.2706 moles of SO₂ + 0.35 moles H₂O

Total moles = 0.9206 moles

Mole fraction SO₂ = 0.2706 moles / 0.9206 moles → 0.29

Now, we can know the partial pressure:

0.29 = Partial pressure SO₂ / Total pressure

0.29 = Partial pressure SO₂ / 1.5 atm

0.29 . 1.5atm = Partial pressure SO₂ → 0.440 atm

8 0
3 years ago
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