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3 years ago

Can sunscreen damage other organisms?

Chemistry

1 answer:

miv72 [106K]3 years ago

5 0

Sunscreen can have negative effects on corals and other marine organisms under certain circumstances.

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Select the correct answer.

Artist 52 [7]

I think c cause if he is in a relationship that’s abusive he needs to speak up before it goes way worst.

3 0

3 years ago

What is the mass of a titanium alloy that has a heat of fusion of 422.5 joules/gram and requires 2,960 joules of energy to melt

romanna [79]

Answer:- Mass of the titanium alloy is 7.01 g, choice C is correct.

Solution:- The heat of fusion is given as 422.5 joules per gram and it also says that 2960 joules of heat is required to melt the metal completely.

The suggested equation is, $Q=mH_f$

where Q is the heat energy, m is the mass and Hf is the heat of fusion.

Since, we are asked to calculate the mass, the equation could be written as:

$m=\frac{Q}{H_f}$

Let's plug in the values in it:

$m=\frac{2960J}{\frac{422.5J}{g}}$

m = 7.01 g

So, the mass of the titanium alloy is 7.01 g, choice C is correct.

7 0

3 years ago

If 200. mL of 0.60 M MgCl2(aq) is added to 400 mL of distilled water, what is the concentration of Mg and Cl in the resulting so

sladkih [1.3K]

Answer:

C. 0.20 M Mg ion & 0.40 M Cl ion

Explanation:

MgCl₂ is a ionic salt which is dissociated as this

MgCl₂ → Mg²⁺ + 2Cl⁻

First of all, we have a solution of 200 mL, with [MgCl₂] = 0.6M

Molarity . volume = moles.

0.6 mol/l . 0.2l = 0.12 mol

MgCl₂ → Mg²⁺ + 2Cl⁻

0.12mol 0.12 0.24

This moles are also in 400mL of water, so the new concentration is

[Mg²⁺] = 0.12 m/0.6L = 0.2M

[Cl⁻] = 0.24 m/0.6L = 0.4M

Remember we initially have 200mL and then, we add 400 mL, so we supose aditive volume. (600mL)

8 0

3 years ago

A sample of 87.6 g of carbon is reacted with 136 g of

Vadim26 [7]

Answer:

A. fluorine, 1.79 moles

Explanation:

Given parameters:

Mass of carbon = 87.7g

Mass of fluorine gas = 136g

Unknown:

The limiting reactant and the maximum amount of moles of carbon tetrafluoride that can be produced = ?

Solution:

Equation of the reaction:

C + 2F₂ → CF₄

let us find the number of the moles the given species;

Number of moles = $\frac{mass}{molar mass}$

C; molar mass = 12;

Number of moles = $\frac{87.7}{12}$ = 7.31moles

F; molar mass = 2(19) = 38g/mol

Number of moles = $\frac{136}{38}$ = 3.58moles

So;

From the give reaction:

1 mole of C requires 2 moles of F₂

7.31 moles of C will then require 2 x 7.31 moles of F₂ = 14.62moles

But we have 3.58 moles of the F₂;

Therefore, the reactant in short supply is F₂ and it is the limiting reactant;

So;

2 moles of F₂ will produce mole of CF₄

3.58 moles of F₂ will then produce $\frac{3.58}{2}$ = 1.79moles of CF₄

6 0

3 years ago

Find the mole fraction of benzene and toluene in solution containing

Mrac [35]

Answer:

The mole fraction of benzene and toluene in solution containing mole fraction of benzene and toluene in solution containing is 45.9%

Explanation:

don't worry

its is correct!

5 0

3 years ago