Answer:
C2H5OH(l) + O2(g) → CO2(g) + ?H2O(l)
The coefficient should be 3
Explanation:
C2H5OH(l) + O2(g) → CO2(g) + ?H2O(l)
The chemical equation is a reaction between ethanol and oxygen . The reaction yield is carbon dioxide and water. Balancing the chemical equation requires one to make the number of atoms on the reactant side be equal to the number of atoms on the product side.
C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(l)
The hydrogen atom on the left hand side of the equation is 6. Therefore, the number of atom of hydrogen should be 6 on the right hand side. The number of oxygen atom on the left hand side is 7. Therefore, the number of Oxygen atom on the right hand side should 7 . Oxygen atom in carbon dioxide(right hand side) is 4 atoms, therefore, it requires 3 atoms of oxygen to make the oxygen atoms 7.
Using 3 as the coefficient of water in the equation will make hydrogen 6 and oxygen 3 .Adding the 3 oxygen to the already 4 atoms of oxygen in carbon dioxide will make oxygen 7 atoms
It applies to both physical and chemical changes.
Carbon cannot reduce sodium because sodium is stronger than carbon. reactive metals like sodium and potassium and electrolysis has to be used.
x= the coefficients in front of the substance in the balanced chemical equation
[H+]= the concentration of hydrogen ions
[A-]= the concentration of the other ion that broke off from the H+
[HA]= the un-disassociated acid concentration
The higher the Ka value, the greater amount of disassociation of the reactants into products. As for acids, they will break down to form H+ ions. The more the H+ ions, the stronger acidity of the solution. Thus since A has the highest Ka value, that represents the strongest acid.
You can determine the Ka value from a number of ways. If equilibrium concentrations are given of a certain acid solution, you can find the proportion of the concentration of ions to the concentration of the remaining HA molecules, using the equation above. Also, pH and KpH can be used in a number of ways. This gets more complicated and depends on the situation, and requires more advanced equations.
Hope this helped a little, its obviously not my best work
