Chemical change because your changing one form to another
Answer:
[H₃O⁺] = 2.5 × 10⁻¹⁰ M
pH = 9.6
Explanation:
Step 1: Given data
Concentration of OH⁻ in the solution ([OH⁻]): 4.0 × 10⁻⁵ M
Step 2: Calculate the concentration of H₃O⁺ in the solution
Let's consider the self-ionization of water.
2 H₂O(l) ⇄ H₃O⁺(aq) + OH⁻(aq)
The <em>ion-product of water (Kw)</em> is:
<em>Kw = 1.0 × 10⁻¹⁴ = [H₃O⁺] × [OH⁻]</em>
[H₃O⁺] = 1.0 × 10⁻¹⁴/[OH⁻]
[H₃O⁺] = 1.0 × 10⁻¹⁴/4.0 × 10⁻⁵
[H₃O⁺] = 2.5 × 10⁻¹⁰ M
Step 3: Calculate the pH of the solution
We will use the following expression.
<em>pH = -log [H₃O⁺]</em>
pH = -log 2.5 × 10⁻¹⁰
pH = 9.6
Answer:
its 57.56
Explanation:
dont ask me how it is just is trust me