Answer:
(3x^2 - 1)(3x^2 + 1)(9x^4 + 1).
Step-by-step explanation:
Using the identity for the difference of 2 squares;
a^2 - b^2 = (a - b)(a + b)
we put a^2 = 81x^8 and b^2 = 1 giving
a = 9x^4 and b = 1, so:
81x^8 − 1 = (9x^4 - 1)(9x^4 + 1)
Applying the difference of 2 squares to 9x^4 - 1:
= (3x^2 - 1)(3x^2 + 1)(9x^4 + 1).
Answer:
A) 4
Step-by-step explanation:
There are a couple of ways to get this but this is how I did it:
1. Multiply the second equation by 1/4 to get the same fraction for y as the one in the first equation
1/4 x + 1/8 y = 2
1/4 (1/3 x + 1/2 y = 4)
1/12 x + 1/8 y = 1
2. Subtract the first equation from the new equation
1/12 x + 1/8 y = 1
<u> - 1/4 x - 1/8 y = -2</u>
-1/6 x= -1
3. Divide both sides by -1/6
<u>-1/6</u> x= <u>-1</u>
-1/6 -1/6
x = 6
4. Substitute 4 in for x in the original equation:
1/4 (6) + 1/8y = 2
6/4 + 1/8y = 2
1/8y = 1/2
y = 4
Area of Trapezoid = (1/2) * (Sum of bases) * height
Area = (1/2) * (11 + 14) * 10
= (1/2) * 25 * 10 = 5 *25 = 125
Area = 125 m²
The equation will be made up of the cost of x number of adult tickets at 74 each which is represented by 74x and youth tickets (an unknown number y) at 35 each which is represented by 35y. We add them together and set them equal to Cost. Cost = 74x + 35y
Answer:
0
Step-by-step explanation:
73x=0
Let's allow ?=x because we need an unknown number.
x=0/73=0
x=0
