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salantis [7]
2 years ago
12

. Liquid alcohol will change to vapor when its temperature reaches the

Chemistry
2 answers:
GREYUIT [131]2 years ago
8 0

Liquid alcohol will change into vapor when the temperature reaches the boiling point.

So my beer ham is safe from my kids to eat

lbvjy [14]2 years ago
5 0
<span>Liquid alcohol will change to vapor when temperature reaches the : D. Boiling point When the temperature reach the boiling point, the molecule that held the liquid's particle together will break free and the particle will scatter. This will cause the liquid substance to undergone a transformation into a Gaseous form</span>
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Answer:

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2 years ago
A teacher uses a bow and arrow to demonstrate accuracy and precision. She shoots several arrows, aiming at the exact center of t
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5 0
3 years ago
Is the mass of .00566 mol of germanium (Ge) greater than one gram or less<br> than one gram?
Salsk061 [2.6K]

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Less than one gram

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8 0
1 year ago
Calculate the OH− concentration after 53 mL of the 0.100 M KOH has been added to 25.0 mL of 0.200 M HBr. Assume additive vol- um
Andre45 [30]

Answer:

\large \boxed{\text{0.0038 mol/L}}

Explanation:

1. Calculate the initial moles of acid and base

\text{moles of acid} = \text{0.0250 L} \times \dfrac{\text{0.200 mol}}{\text{1 L}} = \text{0.005 00 mol}\\\\\text{moles of base} = \text{0.053 L} \times \dfrac{\text{0.100 mol}}{\text{1 L}} = \text{0.0053 mol}

2. Calculate the moles remaining after the reaction

                   OH⁻     +     H₃O⁺ ⟶ 2H₂O

I/mol:      0.0053       0.005 00

C/mol:    -0.00500   -0.005 00

E/mol:      0.0003              0

We have an excess of 0.0003 mol of base.

3. Calculate the concentration of OH⁻

Total volume = 53 mL + 25.0 mL = 78 mL = 0.078 L

\text{[OH}^{-}] = \dfrac{\text{0.0003 mol}}{\text{0.078 L}} = \textbf{0.0038 mol/L}\\\\\text{The final concentration of OH$^{-}$ is $\large \boxed{\textbf{0.0038 mol/L}}$}

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