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EleoNora [17]
3 years ago
7

The table below shows the time that the Moon rose and set over a few days.

Chemistry
1 answer:
Llana [10]3 years ago
4 0

Answer:

C.

rise at 6:20 a.m., set at 4:16 p.m.

Explanation:

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3. A 4.00 gram sample of solid gold was heated from 274K to 314K. How much energy was involved?
MrMuchimi
Q = mcΔT = (4.00 g)(0.129 J/g•°C)(40.85 °C - 0.85 °C)
Q = 20.6 J of energy was involved (more specifically, 20.6 J of heat energy was absorbed from the surroundings by the sample of solid gold).
3 0
3 years ago
If the empirical formula of a compound is CH2, which of the following could be a possible molecular formula for this
DiKsa [7]

Answer:

C2H2

Explanation:

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Which of the following describes the physical state of the layers of the Earth from the outside to the center?
Phantasy [73]
Solid , solid, partially melted, liquid so the answer is D
7 0
3 years ago
Read 2 more answers
1. Which sample contains a total of 9.0 * 10 ^ 23 atoms ? A) 0.50 mole of HCI B) 0.75 mole of H 2 O C) 1.5 moles of Cu D) 1.5 mo
Alchen [17]

c. 1.5 moles of Cu will contain a total of 9.0 * 10 ^ 23 atoms.

Explanation:

To convert moles into atoms,  the molar amount and number of atom is multiplied by Avagadro's number.

Avagadro's number is 6.022×10^{23}  

So applying the formula in the given sample:

A) 0.5×6.022×10^{23}

   3.01×10^{23} atoms.

B) 0.75 mole of H20

O.75×6.022×10^{23}

= 4.5166×10^{23}  atoms.

C) 1.5 moles of Cu

  1.5×6.022×10^{23}

  =  9.033×10^{23}

D). 1.5 moles of H2

1.5 × 2 × 6.022 × 10^{23}

= 18.066 × 10^{23} atoms   because H2 is 2 moles of hydrogen.

Atom is the smallest entity of matter having property of the element to which it is a part.

8 0
3 years ago
g Suppose 0.0350 g M g is reacted with 10.00 mL of 6 M H C l to produce aqueous magnesium chloride and hydrogen gas. M g ( s ) +
iren2701 [21]

Answer:

Mg will be the limiting reagent.

Explanation:

The balanced reaction is:

Mg + 2 HCl → MgCl₂ + H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Mg: 1 mole
  • HCl: 2 moles
  • MgCl₂: 1 mole
  • H₂: 1 mole

Being the molar mass of each compound:

  • Mg: 24.3 g/mole
  • HCl: 36.45 g/mole
  • MgCl₂: 95.2 g/mole
  • H₂: 2 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Mg: 1 mole* 24.3 g/mole= 24.3 g
  • HCl: 2 moles* 36.45 g/mole= 72.9 g
  • MgCl₂: 1 mole* 95.2 g/mole= 95.2 g
  • H₂: 1 mole* 2 g/mole= 2 g

0.0350 g of Mg is reacted with 10.00 mL (equal to 0.01 L) of 6 M HCl.

Molarity being the number of moles of solute that are dissolved in a certain volume, expressed as:

Molarity=\frac{number of moles of solute}{volume}

in units \frac{moles}{liter}

then, the number of moles of HCl that react is:

6 M=\frac{number of moles of HCl}{0.01 L}

number of moles of HCl= 6 M*0.01 L

number of moles of HCl= 0.06 moles

Then you can apply the following rule of three: if by stoichiometry 2 moles of HCl react with 24.3 grams of Mg, 0.06 moles of HCl react with how much mass of Mg?

mass of Mg=\frac{0.06 moles of HCl* 24.3 grams of Mg}{2 moles of HCl}

mass of Mg= 0.729 grams

But 0.729 grams of Mg are not available, 0.0350 grams are available. Since you have less mass than you need to react with 0.06 moles of HCl, <u><em>Mg will be the limiting reagent.</em></u>

7 0
3 years ago
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