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EleoNora [17]
3 years ago
7

The table below shows the time that the Moon rose and set over a few days.

Chemistry
1 answer:
Llana [10]3 years ago
4 0

Answer:

C.

rise at 6:20 a.m., set at 4:16 p.m.

Explanation:

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According to the periodic table, carbon has an atomic mass of 12.011 u. This indicates that the most abundant isotope of carbon
Eduardwww [97]
The most abundant of all of the isotopes of an element will be the one who's mass the mass of element is closest to. In this case, the mass of atomic carbon is closest to the mass of carbon-12.
Thus, Carbon-12 is the most abundant isotope.
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4 years ago
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Which state of matter takes the shape of its container (solids, liquids, gases,).
dimulka [17.4K]

Answer:

solids

Explanation:

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2. Calculate the concentration (in molarity) of a NaOH solution if 25.0 mL of the solution are needed to neutralize 17.4 mL of a
zimovet [89]

Answer:

0.217 M NaOH

Explanation:

M1V1 = M2V2

M1 = 0.312 M HCl

V1 = 17.4 mL HCl

M2 = ?

V2 = 25.0 mL NaOH

Solve for M2 --> M2 = M1V1/V2

M2 = (0.312 M)(17.4 mL) / (25.0 mL) = 0.217 M NaOH

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3 years ago
The chemical combination of the Atoms of two or more elements is known as a/an
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The chemicals combination of the atoms is called a compound.  The bond is formed between the atoms of each of the reacting elements thereby forming a new substance altogether. The compound will often exhibit different characteristics from the originating elements.
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4 years ago
Below is a proposed mechanism for the decomposition of H2O2. H2O2 + I– → H2O + IO– slow H2O2 + IO– → H2O + O2 + I– fast Which of
Savatey [412]

Answer: Option (d) is the correct answer.

Explanation:

The given equations as as follows.

       H_{2}O_{2} + I^{-} \rightarrow H_{2}O + IO^{-}           (slow)

       H_{2}O_{2} + IO^{-} \rightarrow H_{2}O + O_{2} + I^{-}

Therefore, overall reaction equation will be as follows.

     2H_{2}O_{2} + I^{-} + IO^{-} \rightarrow 2H_{2}O + O_{2} + IO^{-} + I^{-}

So, cancelling the spectator ions then the equation will be as follows.

         H_{2}O_{2} \rightarrow 2H_{2}O + O_{2}

As, it is known that slow step of a reaction is the rate determining step. Therefore, rate law for the slow step will be as follows.

        H_{2}O_{2} + I^{-} \rightarrow H_{2}O + IO^{-}

                 Rate law = k[H_{2}O_{2}][I^{-}]

Hence, the reaction is first order with respect to [I^{-}] and it is also first order reaction with respect to [H_{2}O_{2}].

Also, [I^{-}] acts as a catalyst in the reaction.

Thus, we can conclude that the incorrect statement is IO^{-} is a catalyst.

6 0
3 years ago
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