The table below shows the time that the Moon rose and set over a few days.

11) What is the volume of 4.92 grams of hydrogen gas at STP? (Show the work using dimensional analysis)

lorasvet [3.4K]

Answer:

The volume of 4.92 grams of hydrogen gas at STP is 9.105 litter.

Explanation:

We know that, the molecular weight of hydrogen gas $(H_{2} )$ = $1\times 2 = 2$ .

Moles of hydrogen gas = $\frac{weight}{molecular weight} = \frac{4.92}{2} = 2.46$ moles.

At STP, 1 mole of hydrogen gas = occupies 22.4 litter

So, 2.46 mole of hydrogen gas = occupies $\frac{22.4}{2.46} = 9.105$ litter.

Hence, the volume of 2.46 grams of hydrogen gas at STP is 9.105 litter.

4 0

3 years ago

What enzyme catalyses the reaction of PRPP transfer to hypoxanthine with formation of IMP?

Alona [7]

Answer:

HPRT

Explanation:

HPRT catalyzes the salvage reactions of hypoxanthine and guanine with PRPP to form IMP and GMP

The formation of GMP from IMP requires oxidation at C-2 of the purine ring, followed by a glutamine-dependent amidotransferase reaction that replaces the oxygen on C-2 with an amino group to yield 2-amino,6-oxy purine nucleoside monophosphate, or as this compound is commonly known, guanosine monophosphate.

8 0

3 years ago

in a titration 5.0 mL of a 2.0 M NaOH(aq) solution exactly neutralizes 10.0 mL of an HCI(aq) solution. What is the concentration

Hitman42 [59]

Volume of base(NaOH)= Vb =5 mL
Concentration of base(NaOH)= Mb =2 M
Volume of acid(HCl)= Va =10 mL
Concentration of acid(HCl)= Ma = ?
Now,
Ma*Va = Mb*Vb
Ma*(10) = (2)*(5)

Ma= 1M

7 0

4 years ago

You have 750 grams of water at 80° Celsius. Which of the following would lower the temperature of the water by 10° Celsius? (1 p

dem82 [27]

Answer:

adding 750 grams of water at 60° Celsius .

Explanation:

We can calculate the amount of heat lost from 750 grams of water at 80°C to be lowered by 10°C using the relation:

Q = m.c.ΔT,

Where, Q is the amount of heat lost by water (Q = ??? J).

m is the mass of water (m = 750.0 g).

c is the specific heat capacity of the water (c = 4.18 J/g.°C).

ΔT is the temperature difference (ΔT = final T - initial T = - 10.0°C, the temperature of water is lowered by 10.0°C).

∴ Q = m.c.ΔT = (750.0 g)(4.18 J/g.°C)(- 10.0°C) = - 31350.0 J = -31.350 kJ.

Now, we can calculate the Q that is gained by the different added amounts of water:

adding 750 grams of water at 50° Celsius :

ΔT = 70.0°C - 50.0°C = 20.0°C,

∴ Q = m.c.ΔT = (750.0 g)(4.18 J/g.°C)(20.0°C) = 62700.0 J = 62.70 kJ.

adding 325 grams of water at 60° Celsius :

ΔT = 70.0°C - 60.0°C = 10.0°C,

∴ Q = m.c.ΔT = (325.0 g)(4.18 J/g.°C)(10.0°C) = 13585.0 J = 13.585 kJ.

adding 750 grams of water at 60° Celsius :

ΔT = 70.0°C - 60.0°C = 10.0°C,

∴ Q = m.c.ΔT = (750.0 g)(4.18 J/g.°C)(10.0°C) = 31350.0 J = 31.350 kJ.

adding 1000 grams of water at 55° Celsius:

ΔT = 70.0°C - 55.0°C = 15.0°C,

∴ Q = m.c.ΔT = (1000.0 g)(4.18 J/g.°C)(15.0°C) = 62700.0 J = 62.70 kJ.

So, the right choice is:

adding 750 grams of water at 60° Celsius

8 0

4 years ago

Help me pleaseʕ ꈍᴥꈍʔ

vodomira [7]

Answer:

(a) All are correct

Explanation:

catalyst a substance which speeds up a chemical reaction and remains itself unchanged.

example: Iron used in Haber process for the manufacture of ammonia.

5 0

3 years ago

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