Answer:
hey you wanna get it right try this one: 48.0 kcal
was released... at constant pressure.
Explanation:
2KClO₃ → 2KCl + 3O₂
mole ratio of KClO₃ to O₂ is 2 : 3
∴ if moles of O₂ = 5 mol
then moles of KClO₃ =

= 3.33 mol
Mass of KClO₃ needed = mol of KClO₃ × molar mass of KClO₃
= 3.33 mol × ((39 × 1) + (35.5 × 1) + (16 × 3) g/mol
= 407.93 g
The temperature will be 1200K if the volume remained constant
calculation
This is calculated using gay lussac law formula, that is P1/ T1=P2/T2 since the volume is constant
P1 = 100 Kpa
T1= 300 K
P2= 400 Kpa
T2=?
by making T2 the subject of the formula T2 =( P2 xT1)/P1
T2 is therefore = (400 KPa x 300 K) / 100 Kpa = 1200 K