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olga55 [171]
2 years ago
14

7g of gold is heated from 17 degrees C to 42 degrees C. How much energy (heat) was used? The specific heat capacity of gold is .

031cal/gC.
Chemistry
1 answer:
wel2 years ago
7 0
Heat needed=mcθ
=7×0.031×(42-17)
=5.425cal
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What is the limiting reactant when 19.9 g CuO react with 2.02 g H2?
Harlamova29_29 [7]

Answer:

Explanation:

use the equation

moles = mass/mr

=19.9/79.5

=0.250moles of CuO

then do the same for

H = 2.02/1

=2.02

so CuO is the limiting reagent because there is less amount of it.

Hope this helps  :)

4 0
2 years ago
nswer the following questions relating to HCl, CH3Cl, and CH3Br.HCl(g), can be prepared by the reaction of concentrated H2SO4(ag
alexdok [17]

Answer:

It is an example of double displacement reaction.

4.8 g of NaCl is needed to react.

Explanation:

Balanced reaction: H_{2}SO_{4}(aq.)+2NaCl(s)\rightarrow 2HCl(g)+Na_{2}SO_{4}(aq.)

Here, oxidation states of H, S, O, Na and Cl do not change during reaction. Hence it is not a redox reaction.

In this reaction, cations and anions of the reactants interchange their partners during reaction. Hence, it is an example of double displacement reaction.

As H_{2}SO_{4}(aq.) remain in excess amount therefore NaCl (s) is the limiting reagent. Hence production of HCl entirely depends on amount of NaCl used.

Molar mass of HCl = 36.46 g/mol

So, 3.0 g of HCl = \frac{3.0}{36.46} mol of HCl = 0.082 mol of HCl

According to balanced equation-

2 moles of HCl are produced from 2 moles of NaCl

So, 0.082 moles of HCl are produced from 0.082 moles of NaCl

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So, mass of 0.082 moles of NaCl = (0.082\times 58.44) g = 4.8 g

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4 0
3 years ago
Question 3
Assoli18 [71]

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c

Explanation:

8 0
2 years ago
What is the electron configuration of Zn2+
boyakko [2]
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3 years ago
Hydrocarbons, compounds containing only carbon and hydrogen, are important in fuels. The heat of combustion of cyclobutane, C4H8
Gennadij [26K]

Answer:

1. C4H8 + 6O2  -----> 4CO2 + 4H20

2. 3836.77 kcal

Explanation:

1. Balanced equation for the complete combustion of cyclobutane:

C4H8 + 6O2  -----> 4CO2 + 4H20

2. Heat of combustion of cyclobutane = 650.3 kcal/mol

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Energy released during combustion =  5.9 mol × 650.3 kcal/mol = 3836.77kcal

Therefore the energythat  is released during the complete combustion of 331 grams of cyclobutane is 3836.77kcal

8 0
2 years ago
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