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timurjin [86]
3 years ago
14

Some organisms are not able to live in an environment where there is oxygen; these types of organisms are called obligate anaero

bes. Which explanation is most plausible for how they survive without oxygen?
Chemistry
1 answer:
BabaBlast [244]3 years ago
7 0

Answer:

Microorganisms which are killed in the presence of normal concentrations of atmospheric oxygen are called obligate anaerobes.Some species are capable of surviving in upto 8% while other losing viability in 0.5%.They survive without oxygen as they use other molecules as electron acceptor instead of oxygen.

Explanation:In aerobic organisms oxygen is used in cellular respiration as an electron acceptor.oxygen accepts electrons and turns into water H2O or CO2.While obligate anaerobes other molecules as their primary electron acceptors.common electron acceptors used by them are Nitrate NO3-,  Sulphate SO42- or sulphur S,Iron,mercury and manganese.So in this way they undergo respiration and survive without oxygen.

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What is meant by reactive elements​
Vlad1618 [11]

Answer; relative elements are most reactive elements and compounds may ignite spontaneously or explosively. They generally burn in water as well as the oxygen in the air

Explanation:

6 0
3 years ago
How do clouds relate to climate change
Vedmedyk [2.9K]

Answer:

Clouds can block light and heat from the Sun, making Earth's temperature cooler. You've probably noticed this kind of cooldown on a cloudy day. However, some heat from the Sun does get down to Earth. Clouds can trap that heat from the Sun.

Hope that helps :)

4 0
3 years ago
On which side of an equation are the reactants found?
koban [17]
The reactants are found on the Left of the arrow :)
6 0
3 years ago
What is the frequency of the sinusoidal graph?
Arisa [49]

Answer:

For finding frequency, we need to first find the period of the graph.

The period of a sinusoidal graph is the time interval in which it repeats its pattern.

In the graph, we can see, after 1/period time, it repeats its pattern.

Hence the period of the graph is  \pi /2.

Now we need to find its frequency 1/\pi /2

The formula for frequency is 2/\pi

This is the answer

i hope you pass the assignment

try your best!

8 0
3 years ago
Consider the following molecules and the description of the bonding present in each: CH3CH2CH2CH3CH3CH2CH2CH3 (C−CC−C and C−HC−H
denis23 [38]

CH3CH2CH2CH3 < CH3CH2CHO < CH3CHOHCH3

Explanation:

Boiling point trend of Butane, Propan-1-ol and Propanal.

Butane is a member of the CnH2n+2 homologous series is an alkane. Alkanes have C-H and C-C bonds which have Van der waals dispersion forces which are temporary dipole-dipole forces (forces caused by the electron movement in a corner of the atom). This bond is weak but increases as the carbon chain/molecule increases.

In Propan-1-ol(Primaryalcohol), there is a hydrogen bond present in the -OH group. Hydrogen bond is caused by the attraction of hydrogen to a highly electronegative element like Cl-, O- etc. This bond is stronger than dispersion forces because of the relative energy required to break the hydrogen bond. Alcohols (CnH2n+1OH) also experience van der waals dispersion forces on its C-C chain and C-H so as the Carbon chain increases the boiling point increases in the homologous series.

Propanal which is an Aldehyde (Alkanal) with the general formula CnH2n+1CHO. This molecule has a C-O, C-C and C-H bonds only. If you notice, the Oxygen is not bonded to the Hydrogen so there is no hydrogen bond but the C-O bond has a permanent dipole-dipole force caused by the electronegativity of oxygen which is bonded to carbon. It also has van der waals dispersion forces caused by the C-C and C-H as the carbon chain increases down the homologous series. The permanent dipole-dipole forces are not as easy to break as van der waals forces.

In conclusion, the hydrogen bonds present in alcohols are stronger than the permanent dipole-dipole bonds in the aldehyde and the van der waals forces in alkanes (irrespective of the carbon chain in Butane). So Butane < Propanal < Propan-1-ol

3 0
4 years ago
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