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timurjin [86]
3 years ago
14

Some organisms are not able to live in an environment where there is oxygen; these types of organisms are called obligate anaero

bes. Which explanation is most plausible for how they survive without oxygen?
Chemistry
1 answer:
BabaBlast [244]3 years ago
7 0

Answer:

Microorganisms which are killed in the presence of normal concentrations of atmospheric oxygen are called obligate anaerobes.Some species are capable of surviving in upto 8% while other losing viability in 0.5%.They survive without oxygen as they use other molecules as electron acceptor instead of oxygen.

Explanation:In aerobic organisms oxygen is used in cellular respiration as an electron acceptor.oxygen accepts electrons and turns into water H2O or CO2.While obligate anaerobes other molecules as their primary electron acceptors.common electron acceptors used by them are Nitrate NO3-,  Sulphate SO42- or sulphur S,Iron,mercury and manganese.So in this way they undergo respiration and survive without oxygen.

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P4O10(s) = -3110 kJ/mol H2O(l) = -286 kJ/mol H3PO4(s) = -1279 kJ/mol Calculate the change in enthalpy for the following process:
mash [69]

Answer:

-290KJ/mol

Explanation:

ΔHrxn = ΔHproduct - ΔHreactant

ΔHrxn= 4ΔHH3PO4 - {6ΔHH2O + ΔHP4O10}

ΔHrxn = 4(-1279) - [6(-286) - 3110]

= -5116 -(-1716-3110)

= -5116-(-4826)

= -5116 + 4826 = -290KJ/mol

6 0
3 years ago
Put the level of organization in order from smallest to largest a. Organelles, cellsorgans, tissuesorgan systems b. Organs, tiss
Lesechka [4]

Answer: My guess is D i hope this is right

Explanation:

8 0
3 years ago
In a titration, 25.0 mL of 0.500 M KHP is titrated to the equivalence point with NaOH. The final solution volume is 53.5 mL. Wha
Lena [83]
M1v1=m2v2 
m2=(m1v1)/v2 
Where m is the molarities and v is the volumes
<span>m2=(25.0*0.500)/53.5
m2=12.5/53.5
m2=0.2336
by rounding off:
m2=0.234 M
so the answer is C: 0.234 M</span>
3 0
3 years ago
Read 2 more answers
A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 4250 mL of water at 2
Assoli18 [71]

Answer:

The specific heat of copper is 0.385 J/g°C

Explanation:

A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 425 mL of water at 22.55 degrees Celsius. The final temperature of the water was recorded to be 26.15 degrees Celsius. What is the specific heat of the copper?

Step 1: Data given

Mass of copper = 85.2 grams

Temperature of copper = 221.32 °C

Volume of water = 425 mL

Temperature of water = 22.55 °C

Final temperature = 26.15 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculat the specific heat of copper

Heat lost = heat gained

Q = m*c*ΔT

Qcopper = -Qwater

m(copper)*c(copper)*ΔT(copper) = - m(water) * c(water) * ΔT(water)

⇒ m(copper) = 85.2 grams

⇒ c(copper) = TO BE DETERMINED

⇒ ΔT(copper) = the change in temeprature = T2 -T1 = 26.15 -221.32 = -195.17 °C

⇒ m(water) = The mass of water = 425 mL * 1g/mL = 425 grams

⇒ c(water) = The specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature of water = 26.15 - 22.55 = 3.6

85.2 * c(copper) * (-195.17) = -425 * 4.184 * 3.6

c(copper) = 0.385 J/g°C

The specific heat of copper is 0.385 J/g°C

(Note, The original question says the volume of the water is 4250 mL. IF this is not an error, the specific heat of copper is 3.85 J/g°C (10x higher than the normal value).

8 0
3 years ago
AV<br> 5. How many grams are in 0.52 moles of H3PO4?
Hoochie [10]

Answer:

50.96g

Explanation:

Given parameters:

Number of moles of H₃PO₄   = 0.52moles

Unknown:

Mass of the compound  = ?

Solution:

To find the mass of the compound:

    Mass  = number of moles x molar mass of H₃PO₄

Molar mass of H₃PO₄ = 3(1) + 31 + 4(16)  = 98g/mol

  Mass  = 0.52 x 98  = 50.96g

3 0
3 years ago
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