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SSSSS [86.1K]
2 years ago
13

e) Hydrogen gas is a non-metal and can be prepared in a laboratory Explain why hydrogen gas is collected over water.​

Chemistry
1 answer:
Luda [366]2 years ago
3 0

Answer:

to collect pure hydrogen and avoid mixing with air

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Caffeine (C8H10N4O2) is a stimulant found in coffees and teas. When dissolved in water, it can accept a proton from a water mole
Olenka [21]

Answer:

See figure 1

Explanation:

If we want to find the acid and the Brønsted-Lowry base, we must remember the definition for each of these molecules:

-) Acid: hydrogen donor

-) Base: hydrogen acceptor

In the <u>caffeine structure,</u> we have several atoms of nitrogen. These nitrogen atoms have the ability to <u>accept</u> hydronium ions (H^+). Therefore the caffeine molecule will be the base since it can accept

If caffeine is the base, the water must be the acid. So, the water in this reaction donated a hydronium ion.

<u>Thus, caffeine is the base and water the acid. (See figure 1)</u>

3 0
3 years ago
Name the type of chemical reaction : CaO(s) + H2O(l) -----------Ca(OH)2(aq)
Anna [14]
It is called Synthesis reaction
5 0
2 years ago
A student places a starch and water solution into a bag of dialysis tubing and then ties off the ends. Next, he places the fille
Zina [86]

Answer:

After 30 minutes have passed, the solution inside the dialysis tubing and the solution in the beaker will be tested for glucose and starch

-The presence of glucose will be tested with Benedict's solution, Testape®, or Clinistix

4 0
2 years ago
So2+o2 = so3 método de tanteo​
gulaghasi [49]

Answer:

I dont understand

Explanation:

818191919

7 0
3 years ago
What volume (in liters) does 3.91 moles of nitrogen gas at 5.35 atm and 323 K occupy
daser333 [38]
Moles   =  n  = 3.91 mol

                  Pressure  =  P  =  5.35 atm

                  Temperature  =  T  =  323 K

                  Volume  =  V  =  ?

Formula used: Ideal Gas Equation is used,

                                        P V  = n R  T
Solving for V,
                                           V  =  n R T / P
Putting Values,
                           V  =  (3.91 mol × 0.0825 atm.L.mol⁻¹.K⁻¹ × 323 K) ÷ 5.35 atm

                         V  =  19.36 L

5 0
3 years ago
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