<u>Answer:</u> The mass percent of water in the original air sample is 4.16 %
<u>Explanation:</u>
We are given:
Volume of moist air = 12.0 L
Volume of dry air = 11.50 L
Volume of water lost = (12.0 - 11.50) L = 0.50 L
Here, the percent by mass ratio will be equal to the percent by volume ratio as the number of moles is directly related to the volume.
To calculate the volume percentage of water in the air, we use the equation:

Putting values in above equation, we get:

Hence, the mass percent of water in the original air sample is 4.16 %
Answer:
The experimental feature of the MALDI-MS technique which allows the separation of ions formed after the adduction of tissue molecules:
B) Velocity of ions depends on the ion mass-to-charge ratio.
Explanation:
- The option a is not correct as distance traveled by ions doesn't depend upon the ion charge rather it depends upon time for which you leave the sample to run.
- The option b is correct as velocity of ions depends on the ion mass-to-charge ratio because separation is done due to mass to charge ratio feature.
- The option c is incorrect as time of travel is not inversely proportional to the ion-to-mass ratio because the ion will move across the gel until you stop the electric field.
- The option d is not correct as electric field between MALDI plate and MS analyzer is though uniform but this feature doesn't allow the separation of ions.
Answer:
It was called The Step Reconer