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choli [55]
3 years ago
10

What are groups 1, 2, and 3 examples of on the periodic table? A. Nonmetals B. Metals C. Noble gases D. Metalloids

Chemistry
2 answers:
crimeas [40]3 years ago
8 0
They are examples of B. Metals on the periodic table.
tankabanditka [31]3 years ago
3 0

The correct answer is:

Metals

They are all alkali and transition metals

Explanation:

The periodic table includes elements clustered into groups with comparable properties. Alkali metals are reactive, soft metals with low densities. Transition metals are unreactive metals that have many have common uses. Halogens are reactive non-metals that form glowing vapors.



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Number of SO2 molecules in 1.28 mol of SO2
dolphi86 [110]

Answer:

7.7056 x 10^23

6 0
3 years ago
Given the following partial (valence-level) electron configurations,<br> (a) identify each element,
Kamila [148]

The arrangement of electrons within an atom is called the electronic configuration and the electrons are filled up according to the energy of the levels as: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f.

<h3>What is the difference between electron configuration and valence electron configuration?</h3>

Electron configuration is the number of electrons that are present in the atom and is repressed through the different sub-shells. So for example, the electron configuration for oxygen is 1s^2 2s^2 2p^4. While the valence electrons only refer to the electrons in the outermost shell of the atom.

<h3>What is a partial orbital diagram?</h3>

A partial orbital diagram shows only the highest energy sublevels being filled. Al (Z = 13) 1s22s22p63s23p1. A condensed electron configuration has the element symbol of the previous noble gas in square brackets. Al has the condensed configuration [Ne]3s23p1.

Learn more about electronic configuration here:

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4 0
2 years ago
Select the correct answer from each drop-down menu.
seraphim [82]

1. protons and neutrons

2. electrons

5 0
3 years ago
Read 2 more answers
Please help me with this question!!
mestny [16]

Answer: 824.6 g of NaCl are produced from 500.0 g of chlorine.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}  \text{Moles of} Cl_2=\frac{500.00g}{71g/mol}=7.04moles

2Na+Cl_2\rightarrow 2NaCl  

According to stoichiometry :

1 mole of Cl_2 produce = 2 moles of NaCl

Thus 7.04 moles of Cl_2 will produce=\frac{2}{1}\times 7.04=14.08moles  of NaCl

Mass of NaCl=moles\times {\text {Molar mass}}=14.08moles\times 58.5g/mol=824.26g

Thus 824.6 g of NaCl are produced from 500.0 g of chlorine.

3 0
3 years ago
N the reaction 2Cu2O(s) → 4Cu(s) + O2(g) how does the oxidation number of the copper atoms change
Usimov [2.4K]

Answer: The oxidation number of Cu decreased

Explanation: In Cu2O equation Cu has an oxidation number of

Cu+1 O-2

then in the product side Cu is represented as a single element.

The rule on oxidation number for an individual element is always O

So Cu has 0 oxidation number.

8 0
3 years ago
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