Answer:
The solution is .
Step-by-step explanation:
A first order differential equation is called a separable equation if the function
can be factored into the product of two functions of
and
:
where and
are continuous functions.
We have the following differential equation
In the given case and
.
We divide the equation by and move
to the right side:
Next, integrate both sides:
Now, we solve for
We use the initial condition to find the value of C.
Therefore,
Answer:
(3, 0).
Step-by-step explanation:
dentifying the vertices of the feasible region. Graphing is often a good way to do it, or you can solve the equations pairwise to identify the x- and y-values that are at the limits of the region.
In the attached graph, the solution spaces of the last two constraints are shown in red and blue, and their overlap is shown in purple. Hence the vertices of the feasible region are the vertices of the purple area: (0, 0), (0, 1), (1.5, 1.5), and (3, 0).
The signs of the variables in the contraint function (+ for x, - for y) tell you that to maximize C, you want to make y as small as possible, while making x as large as possible at the same time.
Hence, The Answer is ( 3, 0)
Step-by-step explanation:
The domain and range of a function and its inverse are inverted i.e. The domain of the function will become range of its inverse and the range of the function will become the domain of its inverse.
When representing the function in ordered pairs, the first values in the pair represents the domain and second values represent the range of the function.
h(x) = {3,5),(5,-7)(6,-9)(10,-12)(12,16)}
Domain of h(x) is: {3, 5, 6, 10, 12}
Range of h(x) is: (5, -7, -9, -12, 16}
So,
Domain of = Range of h(x) = (5, -7, -9, -12, 16}
Range of = Domain of h(x) = {3, 5, 6, 10, 12}
Therefore, will be represented as:
{(5,3), (-7,5), (-9, 6), (-12, 10), (16,12)}
It seems like you have made some error while writing the original function because of which we are not getting an exact match in the answer. However by looking at the answers, option B is the nearest most and seems the correct answer.