Answer:
y = 9x
Step-by-step explanation:
You can set up linear equations like this: y = mx + b, where m is the slope or rate, and b is the y-intercept.
9 would be the slope, since he has to pay $9 per gift.
The y-intercept is when x = 0, but if he doesn't buy any gifts, he won't have to pay anything, so b = 0. You don't have to include it since it's 0.
So, it's just y = 9x
Hope that helps! :D
Answer:
The price of the computer is $1,152
Step-by-step explanation:
Let the price of the computer be $x
The first boy boy had 7/8 of this amount, the amount he has is thus 7/8 × $x = 7x/8
The second boy had 5/6 of what the first boy had. The amount of money he has is thus 5/6 × 7x/8 = 35x/48
Now, the addition of what they have is $696 more than what they need to pay. This amount is x+ 696
Mathematically, this can be represented as;
7x/8 + 35x/48 = x + 696
(42x + 35x)/48 = (x + 696)
77x/48 = (x + 696)
77x = 48(x + 696)
77x = 48x + 33408
77x - 48x = 33408
29x = 33, 408
x = 33,408/29
x = $1,152
The graph of f(x) = |x| would look like the image below.
Answer:
The 3 possible values of x are;
6, 4 and 2
Step-by-step explanation:
If the triangle is isosceles, then two of the sides must be equal
So we equate the sides, 2 at a time to get the different values of x
3x + 4 = 2x + 10
3x-2x = 10-4
x = 6
3x + 4 = x + 12
3x-x = 12-4
2x = 8
x = 8/2 = 4
2x + 10 = x + 12
2x - x = 12-10
x = 2
Answer:
(3x+4)(5x+7)
Step-by-step explanation:
15x^2
+41x+28
Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2
+ax+bx+28. To find a and b, set up a system to be solved.
a+b=41
ab=15×28=420
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.
1,420
2,210
3,140
4,105
5,84
6,70
7,60
10,42
12,35
14,30
15,28
20,21
Calculate the sum for each pair.
1+420=421
2+210=212
3+140=143
4+105=109
5+84=89
6+70=76
7+60=67
10+42=52
12+35=47
14+30=44
15+28=43
20+21=41
The solution is the pair that gives sum 41.
a=20
b=21
Rewrite 15x^2
+41x+28 as (15x^2
+20x)+(21x+28).
(15x^2
+20x)+(21x+28)
Factor out 5x in the first and 7 in the second group.
5x(3x+4)+7(3x+4)
Factor out common term 3x+4 by using distributive property.
(3x+4)(5x+7)
