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3 years ago

THE RIGHT ANSWERRRRRR

Mathematics

1 answer:

Mkey [24]3 years ago

4 0

Area of semicircle = 1/2 the area of a circle:
$A_{sc}=\frac{1}{2} \pi r^{2}$
radius is half the diameter of 6ft.
$A_{sc} = \frac{1}{2} \pi (3^{2} )=14.13 ft^{2} .$
Area of the rectangle:
$A_{r} =lw=15*6=90 ft^{2} .$
Add the two together:
90 + 14.13 = 104.13
Round to the nearest tenth (one decimal place)
Area = 104.1 square feet.

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In the circle below, if < B = 46°, what is the measure of arc AB?

olganol [36]

angle B = ( arc ADB ) ÷ 2

46 = ( arc ADB ) / 2

Multiply both sides by 2

46 × 2 = 2 × ( arc ADB ) / 2

92 = arc ADB

arc AB = arc ADB

arc AB = 92

8 0

3 years ago

Please let me know the correct answer.

NNADVOKAT [17]

Set h to 640 and solve for t:

640 = -490t^2 + 1120t

Subtract 640 from both sides:

-490t^2 + 1120t - 640 = 0

The formula to solve a quadratic equation is:

x = -b -/+ sqrtroot (b^2-4ac)/(2a) where a = -490, b = 1120 and c = -640

Solve:

x = -1120 -/+ sqrtroot (1120^2-4(-490)(-640) )/ 2(-490)

x = 8/7 = 1.1428 = 1.14

Time was 1.14 seconds

4 0

3 years ago

Wrong answers will be reported

PIT_PIT [208]

The solution to the equation is p = 1/3 and q = undefined

<h3>How to solve the equation?</h3>

The equation is given as:

p^2 - 2qp + 1/q = (p - 1/3)

The best way to solve the above equation is by the use of a graphing calculator i.e. graphically

However, it can be solved algebraically too (to some extent)

Recall that the equation is given as:

p^2 - 2qp + 1/q = (p - 1/3)

Split the equation

So, we have

p^2 - 2qp + 1/q = 0

p - 1/3 = 0

Solve for p in p - 1/3 = 0

p = 1/3

Substitute p = 1/3 in p^2 - 2qp + 1/q = 0

So, we have

(1/3)^2 - 2q(1/3) + 1/q = 0

This gives

1/9 - 2/3q + 1/q = 0

This gives

2/3q + 1/q = -1/9

Multiply though by q

So, we have

2/3q^2 + 1 = -1/9q

Multiply through by 9

6q^2 + 9 = -q

So, we have

6q^2 + q + 9 = 0

Using the graphing calculator, we have

q = undefined

Hence. the solution to the equation is p = 1/3 and q = undefined