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lina2011 [118]
3 years ago
12

Round 4,982 to the nearest hundred

Mathematics
2 answers:
FromTheMoon [43]3 years ago
8 0
The next nearest hundred for this equation is 1,000 so the answer is 5,000. 
I hope this helps ;)
Brums [2.3K]3 years ago
8 0
The answer is 5,000 because you have to look at the place value that's next to the 4 and if its higher or  above give it a shove and that should be your anser
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If preimage is (0, 1) . (4, 0), (4, 1) , what are the points after a translation of 3 units up and then a reflection over the -a
yulyashka [42]

Answer:

(0, 4) (-4, 3) (-4, 4)

Step-by-step explanation:

Translation rules:

Units UP - Add to the y-coordinate.

Units DOWN - Subtract from the y-coordinate.

Units RIGHT - Add to the x-coordinate.

Units LEFT - Subtract from the x-coordinate.

--------------------------------------------------------------------------------------------------------------

In this case, the word problem is asking for the points after a translation of 3 units up.

(x, y+3)

(0,1) → (0,4)

(4,0) → (4,3)

(4,1) → (4,4)

--------------------------------------------------------------------------------------------------------------Now it's time to reflect the new points over the y-axis.

When reflecting over the y-axis, the y-coordinate remains the same, but the x-coordinate becomes the opposite value. (-x, y)

(0,4) → (0,4)

(4,3) → (-4,3)

(4,4) → (-4,4)

3 0
3 years ago
What’s the y-intercept? Why?
ella [17]

Answer:

2

Step-by-step explanation:

Because it goes into the positives and then comes out to be 2

8 0
3 years ago
Read 2 more answers
6
ioda
$6.060606- because in this situation she has $10 and the rate is $1.65 with no additional rate or fee.
So you would need to do 10/1.65 and round it down to find the whole or keep the decimals to get an exact answer
Answer:6.060606
5 0
3 years ago
Help on number nine please?​
AURORKA [14]

im pretty sure true because they do not intersect and are not parallel :)

7 0
4 years ago
Determine the zeros of r=2sin5theta
vazorg [7]

Answer:

\theta=\frac{n\pi}{5}

Step-by-step explanation:

You have the following function:

r=2sin5\theta          (1)

In order to find the zeros of the function you equal to zero the equation (1), and then you solve for θ:

2sin5\theta=0\\\\sin5\theta=0\\\\5\theta=sin^{-1}(0)=n\pi;\ \ \ \ n=0,1,2,3,..\\\\\theta=\frac{n\pi}{5}

Then, there are infinite zeros for the function of the equation (1), because n has infinite positive integers values.

6 0
3 years ago
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