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lina2011 [118]
3 years ago
12

Round 4,982 to the nearest hundred

Mathematics
2 answers:
FromTheMoon [43]3 years ago
8 0
The next nearest hundred for this equation is 1,000 so the answer is 5,000. 
I hope this helps ;)
Brums [2.3K]3 years ago
8 0
The answer is 5,000 because you have to look at the place value that's next to the 4 and if its higher or  above give it a shove and that should be your anser
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22 students is __% of 50 is 10
nekit [7.7K]

Answer: it might be 0.22 or 0.50

Step-by-step explanation:

cause i did 22/100 and 50/100 and got these answer one of them might be right or both of them are wrong. This is what i think so.

6 0
3 years ago
Anyone know the answer?? ( I got confused half way)
weqwewe [10]
The answer is 8 and 3 fourths which would be written as 8 3/4
7 0
3 years ago
Read 2 more answers
Devon is 30 years older than his son, Milan. The sum of both their ages is 48. Using the variables d and m to represent the ages
statuscvo [17]

Answer+Step-by-step explanation:

m = man's age

s = son's age

m=s+36

(m+8)=3*(s+8)

Resolves to: s=10, m=46

So the man is 46 (=10+36).

In 8 years, son is 18 (=10+8), man is 54 (=3*18 and 46+8), thank you.

5 0
3 years ago
Solve 4(4f-9)=-(2-f)
Whitepunk [10]

Answer:

f = \frac{7}{15}

Step-by-step explanation:

1. 4(4f - 9) = -(2-f)               distribute the negative

2. 4(4f - 9) = -2 + f           Distribute the 4

3. 16f - 9 = -2 + f            Subtract f on both sides

4. 15f - 9 = -2                  Add 9 on both sides

5. 15f = 7                 Divide both equations by 15

6. \frac{15f}{15} = \frac{7}{15}  

f = \frac{7}{15}

8 0
4 years ago
Find the sum of 1 + 3/2 + 9/4 + …, if it exists.
zmey [24]

Answer:

Option (4)

Step-by-step explanation:

Given sequence is,

1+\frac{3}{2}+\frac{9}{4}..........

We can rewrite this sequence as,

1+\frac{3}{2}+(\frac{3}{2})^2.............

There is a common ratio between the successive term and the previous term,

r = \frac{\frac{3}{2}}{1}

r = \frac{3}{2}

Therefore, it's a geometric sequence with infinite terms. In other words it's a geometric series.

Since sum of infinite geometric sequence is represented by the formula,

S_{n}=\frac{a}{1-r}  , when r < 1

where 'a' = first term of the sequence

r = common ratio

Since common ratio of the given infinite series is greater than 1 which makes the series divergent.

Therefore, sum of infinite terms of a series will be infinite Or the sum is not possible.

Option (4) will be the answer.

3 0
4 years ago
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