On the basis of which property of the elements are they divided into metals and non metals?

Determine the value of the equilibrium constant, KgoalKgoalK_goal, for the reaction CO2(g)⇌C(s)+O2(g)CO2(g)⇌C(s)+O2(g), Kgoal=?

NISA [10]

Answer:

The value of the equilibrium constant for reaction asked is $1.24\times 10^{-7}$ .

Explanation:

$CO_2(g)\rightleftharpoons C(s)+O_2(g)$

$K_{goal}=?$

$K_{goal}=\frac{[C][O_2]}{[CO_2]}$

$2CO_2(g)+2H_2O(l)\rightleftharpoons CH_3COOH(l)+2O_2(g)$ ..[1]

$K_1=\frac{[CH_3COOH][O_2]^2}{[CO_2]^2[H_2O]^2}$

$2H_2(g)+O2(g)\rightleftharpoons 2H_2O(l)$ ..[2]

$K_2=\frac{[H_2O]^2}{[H_2]^2[O_2]}$

$CH_3COOH(l)\rightleftharpoons 2C(s)+2H_2(g)+O_2(g)$ ..[3]

$K_3=\frac{[C]^2[H_2]^2[O_2]}{[CH_3COOH]}$

[1] + [2] + [3]

$2CO_2(g)\rightleftharpoons 2C(s)+2O_2(g)$

( on adding the equilibrium constant will get multiplied with each other)

$K=K_1\times K_2\times K_3$

$K=5.40\times 10^{-16}\times 1.06\times 10^{10}\times 2.68\times 10^{-9}$

$K=1.53\times 10^{-14}$

$K=\frac{[C]^2[O_2]^2}{[CO_2]^2}$

On comparing the K and $K_{goal}$ :

$K^2=K_{goal}$

$K_{goal}=\sqrt{K}=\sqrt{1.53\times 10^{-14}}=1.24\times 10^{-7}$

The value of the equilibrium constant for reaction asked is $1.24\times 10^{-7}$ .

4 0

3 years ago

The lowest value of the henry's law for methane gas (ch4) will be obtained with __________ as the solvent and a temperature of _

NikAS [45]

The lowest value of the henry's law for methane gas (CH₄) will be obtained with H₂O as the solvent and a temperature of 349 K.

Henry's law: This law states that at a constant temperature, the amount of a gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas that in equilibrium with that liquid.

Mathematically it can be written as:

$C_{g}=k\times P_{g}$

So, for the methane gas , lowest value of the henry's law obtained at 349 K and with H₂O as the solvent.

3 0

3 years ago

. The kidneys are _______________ to the liver.

m_a_m_a [10]

I’d say posterior because the right kidney is slightly above where the liver is

7 0

3 years ago

A swimming pool is 5.0 m long, 4.0 m wide and 3.0 m deep. Compute the force exerted by the water against

Alona [7]

For the answer to the question above, ater weights 1000kg per meter cubed. the volume of the pool is part A is 5*4*3 = 60 meters cubed 
60*1000 = 60 000kg. the force from this is m*g = 60 000 * 9.81 = 588kN 

part B: 
volume: 4*4*3 = 48 meters cubed 
48 * 1000 = 48000kg 
F = 9.81*48000 = 470kN
I hope this helps.

6 0

4 years ago

If a sodium ion (Na+) has a positive charge and loses an electron when combined with chlorine, will the sodium atom become a new

Alina [70]

Answer:

No

Explanation:

loss of electron doesn't affect the element.

only change in proton number can, as we notice in nuclear chemistry.

please mark brainliest

7 0

3 years ago