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yuradex [85]
3 years ago
14

How can a charged atom (an ion) attract a neutral atom? 1. the charged atom can hit the neutral atom and make it positively char

ged or negatively charged. 2. an ion polarizes a nearby neutral atom, so that the part of the atom nearer to the ion acquires a charge opposite to the charge of the ion, and the part of the atom farther from the ion acquires a charge of the same sign as the ion. 3. the charged atom can produce secondary electrons to interact with the neutral atom and make it positively charged or negatively charged. 4. the charged atom can emit x-rays to induce ionization of the neutral atom?
Chemistry
1 answer:
Ivan3 years ago
8 0
The answer would be 2. <span>an ion polarizes a nearby neutral atom, so that the part of the atom nearer to the ion acquires a charge opposite to the charge of the ion, and the part of the atom farther from the ion acquires a charge of the same sign as the ion

In neutral atoms, the negative and positive charge spread evenly. The charge from an ion could create an electric field that will attract the charge of the neutral atoms.
The neutral atoms charge sum still zero, but the distribution of charge could be changed.</span>
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Which of the following rules should you follow to balance chemical equations?
Firdavs [7]

Answer:

c. add coefficients as needed

Explanation:

A chemical equation is defined as the equation that shows changes in a chemical reaction. A chemical equation consist of reactant and product, reactant is at left side of the arrow and product is at right side of the arrow.

Reactant => Product

While balancing a chemical equation, the basic rule is to balance the coefficient as required. Coefficient represents the number of molecules and is used at front of a chemical symbol. Change in coefficient helps balance the number of atoms or molecules of the substances on both the sides of the arrow.

Subscripts are never allowed to change because it can change the chemical involved in the reaction.

Hence, the correct answer is "c. add coefficients as needed".

3 0
2 years ago
Report the number 315.05 to 3 significant figures.
emmainna [20.7K]

Answer:

315.

Explanation:

Hello.

In this case, since the given number has five significant figures as the zero is to the right of the first nonzero digit (3), if it is required to report it with three significant figures, it is necessary to "cut" it at the first five without any rounding since the subsequent zero is less than five.

Thus the number turns out:

315

Best regards.

5 0
3 years ago
How are the shape of sand dunes determined?using one word
SVEN [57.7K]
"windweathered" because the use of wind weathering would bring the sand all around and it would be wind weathered
8 0
3 years ago
Describe what you know about the motion of particles.
garik1379 [7]

The motion of particles can be changed by the temperature you put it at.

7 0
3 years ago
26.6 mL of 2.50 M stock solution of sucrose is diluted to 50.0 mL. A 16.0 mL sample of the resulting solution is then diluted to
frozen [14]

Answer:

In the final solution, the concentration of sucrose is 0.126 M

Explanation:

Hi there!

The number of moles of solute in the volume taken from the more concentrated solution will be equal to the number of moles of solute in the diluted solution. Then, the concentration of the first solution can be calculated using the following equation:

Ci · Vi = Cf · Vf

Where:

Ci = concentration of the original solution

Vi = volume of the solution taken to prepare the more diluted solution.

Cf = concentration of the more diluted solution.

Vf = volume of the more diluted solution.

For the first dillution:

26.6 ml · 2.50 M = 50.0 ml · Cf

Cf = 26.6 ml · 2.50 M / 50.0 ml

Cf = 1.33 M

For the second dilution:

16.0 ml · 1.33 M = 45.0 ml · Cf

Cf = 16.0 ml · 1.33 M / 45.0 ml

Cf = 0.473 M

For the third dilution:

20.0 ml · 0.473 M = 75.0 ml · Cf

Cf = 20.0 ml · 0.473 M / 75.0 ml

Cf = 0.126 M

In the final solution, the concentration of sucrose is 0.126 M

7 0
2 years ago
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