When the little fish die they sink to the bottom, and after time the skeletons build up on top of each other.
Answer:
50 g of K₂CO₃ are needed
Explanation:
How many grams of K₂CO₃ are needed to make 500 g of a 10% m/m solution?
We analyse data:
500 g is the mass of the solution we want
10% m/m is a sort of concentration, in this case means that 10 g of solute (K₂CO₃) are contained in 100 g of solution
Therefore we can solve this, by a rule of three:
In 100 g of solution we have 10 g of K₂CO₃
In 500 g of solution we may have, (500 . 10) / 100 = 50 g of K₂CO₃
C: 12.0107 g/mol ≅ 12.00 g/mol
H: 1.00784 g/mol ≅ 1.008 g/mol
O: 15.999 g/mol ≅ 16.00 g/mol
n(molar mass of CH2O)= 180
n.30=180
n=6
molecular formula: c6h12o6 glucose
Answer:
2 M
Explanation:
mole weight of CaBr2 = 40 + 2 * 79.9 = 199.8 gm
20 gm is then 20/199.8 =.1 mole
.1 mole / .50 liter = 2 M
Answer:
1.8×10^-2mm or 0.018mm
Explanation:
Density = mass/Volume
But volume= area×thickness
Area= 50ft2= 46451.52cm2
Mass=8oz= 226.7962g
Density= 2.70g/cm3
Thickness= mass/density ×area
= 226.7962/46451.52×2.70= 1.8×10-3cm= 1.8×10^-2mm
