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2 years ago

End the name of the second element with the suffix _____.

Chemistry

1 answer:

gulaghasi [49]2 years ago

5 0

Answer:

ide

in binary ionic compounds, you change the suffix of the nonmetal to ide. example: sodium chlorIDE

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PLEASE HELP!!!

algol [13]

Question 1 answer: A

Question 2 answer: H

Question 3 answer: J

Question 4 answer: T

8 0

3 years ago

an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a tem

OleMash [197]

Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

Explanation:

Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

$P\cdot V = n\cdot R\cdot T$ ,

$\displaystyle V = \frac{n\cdot R\cdot T}{P}$ .

where

$P$ is the pressure of the gas,
$V$ is the volume of the gas,
$n$ is the number of moles of particles in this gas,
$R$ is the ideal gas constant, and
$T$ is the absolute temperature of the gas (in degrees Kelvins.)

The numerical value of $R$ will be $8.314$ if $P$ , $V$ , and $T$ are in SI units. Convert these values to SI units:

$P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa$ ;
$V$ shall be in cubic meters, $\rm m^{3}$ ;
$T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K$ .

Apply the ideal gas law:

$\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}$ .

4 0

3 years ago

A(n) ______________ is an organism that lives on another organism and causes harm to that organism

RoseWind [281]

Answer: The answer is Parasite ma dude

Explanation:

In evolutionary ecology, parasitism is a symbiotic relationship between species, where one organism, the parasite, lives on or in another organism, the host, causing it some harm, and is adapted structurally to this way of life.

Hopes this helps

8 0

3 years ago

Read 2 more answers

The mole fraction of NaCl in an

AlekseyPX

Answer:

Moles of water are 0.868

Explanation:

7 0

3 years ago

How many kg of carbon dioxide are used per year to produce their arm and hammer baking soda?

cestrela7 [59]

The complete question would be as follows:

700,000 tons of baking soda are produced per year. How many kilograms of carbon dioxide are used per year to produce baking soda?

We calculate as follows:

CO2(g) + NH3(aq) + NaCl(aq) + H2O -----> NaHCO3(s) + NH4Cl(aq)

700000 tons NaHCO3 ( 907.185 kg / 1 ton ) (1 kmole NaHCO3 / 84.0 kg NaHCO3) x (1 kmole CO2 / 1 kmole NaHCO3) x (44.0 kg CO2 / 1 kmole) = 3x10^8 kg CO2

Hope this answers the question. Have a nice day.

3 0

3 years ago