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Natalka [10]
3 years ago
11

End the name of the second element with the suffix _____.

Chemistry
1 answer:
gulaghasi [49]3 years ago
5 0

Answer:

ide

in binary ionic compounds, you change the suffix of the nonmetal to ide. example: sodium chlorIDE

You might be interested in
Phosphorus has three electrons in its 3p sublevel and sulfur has four. Phosphorus should have the lower ionization energy but it
Nadya [2.5K]

Answer:

B

Explanation:

First of all it is important to know that a half filled orbital is particularly stable. In phosphorus all the electrons occur singly in the 3p sublevel minimizing inter electronic repulsion hence it is more difficult to remove an electron from this energetically stable arrangement. In sulphur, electrons are paired in one of the 3p orbitals thereby lowering the energy of that level due to instability caused by interelectronic repulsion between two electrons in the same orbital.

8 0
3 years ago
11. As early as 1938. the use of NaOH was suggested as a means of removing CO2 from the cabin of a spacecraft according to the f
vagabundo [1.1K]

For a (unbalanced) reaction: NaOH +CO2-Na2CO3 + H2O, the moles of NaOH and moles of each product are formed are mathematically given as

a) Moles of NaOH =44.05

b)   Moles of Na2CO3=21.0

  • Moles of H2O= 21.0

<h3>What is the moles of NaOH and what moles of each product are formed?</h3>

Generally, the equation for the Chemical reaction  is mathematically given as

2 NaOH(aq)+ CO2(g)------> Na2CO3(aq)+ H2O(l)

Therefore

Moles of CO2= 925/44

Moles of CO2=21.0

Hence

Moles of NaOH = 2 x Moles of CO2

Moles of NaOH = 2x925/44

Moles of NaOH =44.05

In conclusion

Moles of Na2CO3 925/44

Moles of Na2CO3=21.0

And

Moles of H2O= 925/44

Moles of H2O= 21.0

Read more about Chemical reaction

brainly.com/question/16416932

3 0
2 years ago
You need to produce a buffer solution that has a pH of 5.50. You already have a solution that contains 10 mmol (millimoles) of a
balandron [24]

Answer:

56.9 mmoles of acetate are required in this buffer

Explanation:

To solve this, we can think in the Henderson Hasselbach equation:

pH = pKa + log ([CH₃COO⁻] / [CH₃COOH])

To make the buffer we know:

CH₃COOH  +  H₂O  ⇄   CH₃COO⁻  +  H₃O⁺     Ka

We know that Ka from acetic acid is: 1.8×10⁻⁵

pKa = - log Ka

pKa = 4.74

We replace data:

5.5 = 4.74 + log ([acetate] / 10 mmol)

5.5 - 4.74 = log ([acetate] / 10 mmol)

0.755 = log ([acetate] / 10 mmol)

10⁰'⁷⁵⁵ = ([acetate] / 10 mmol)

5.69 = ([acetate] / 10 mmol)

5.69 . 10 = [acetate] → 56.9 mmoles

6 0
3 years ago
How many liters of H2O gas are produced when
anyanavicka [17]
1 mole C3H8 produces 4 moles H2O. So, first we convert 32 grams of propane to moles and then find moles of H2O. Then convert moles of H2O to grams of H2O
Moles of H2O produced = 32 g C3H8 x 1 mole/44 g x 4 moles H2O/mole C3H8 = 2.909 moles H2O
Grams H2O produced = 2.909 moles H2O x 18 g/mole = 52.36 g = 52 g H2O
8 0
2 years ago
make a 450 gram solution with the mass by mass concentration of 7% how much salt and water do you need to mix​
Elis [28]
You’d need to mix over have the mass of the 450 gram solution
3 0
3 years ago
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