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Kazeer [188]
4 years ago
12

Approximately how long are fossil fuels going to last (at the present level of consumption)?

Physics
1 answer:
Murljashka [212]4 years ago
5 0

Answer:

Oil : about 50years

Gas: about 52years

Coal: about 114years

Explanation:

Oil

Globally, we currently consume the equivalent of over 11 billion tonnes of oil from fossil fuels every year. Crude oil reserves are vanishing at a rate of more than 4 billion tonnes a year, so if we carry on as we are, our known oil deposits could run out in just about 50 years.

Gas

If we increase gas production to fill the energy gap left by oil, our known gas reserves only give us just 52 years left.

Coal

Although it’s often claimed that we have enough coal to last hundreds of years, this doesn’t take into account the need for increased production if we run out of oil and gas.

If we step up production to make up for depleted oil and gas reserves, our known coal deposits could be gone in 114 years.

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A particle oscillates harmonically x = A cos(ωt + φ0), with amplitude 9 m, angular frequency π s −1, and initial phase π 3 radia
Gekata [30.6K]

Answer:

t = \frac{5}{12} s

Explanation:

As we know that the equation of particle position is given as

x = A cos(\omega t + \phi_0)

Now the speed of the particle is given as

v = A\omega sin(\omega t + \phi_0)

now we know that potential energy and kinetic energy is equal

so we have

\frac{1}{2} mv^2 = \frac{1}{2}kx^2

so we will have

A^2\omega^2 sin^2(\omega t + \phi_0) = A^2\omega^2 cos^2(\omega t + \phi_0)

tan^2(\omega t + \phi_0) = 1

\omega t + \phi_0 = \frac{\pi}{4} or \frac{3\pi}{4}

\pi t = \frac{3\pi}{4} - \frac{\pi}{3}

\pi t = \frac{5\pi}{12}

t = \frac{5}{12} s

6 0
3 years ago
Problem 18.9 an underwater diver sees the sun 60 ∘ above horizontal. part a how high is the sun above the horizon to a fisherman
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The angles in the equation are not the angles relative to the horizon but are relative to the "normal" which means that the line that is perpendicular to the surface.

The angle under the water is 90 – 60 = 30. 

n1 for water is 1.33, n2 for air is 1 Which you seem to understand. 

(1.33)(sin (30)) = (1.00)(sin (x2)) 

Rearranging the equation above, will give us: x^2 = sin^-1((1.33 sin 30)/1) = 41.68

But remember that that is the angle relative to the normal so you have to deduct it from 90 to get the angle relative to the horizon and you get (90 – 41.68) = 48.32 degrees.

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