1: Equilibrium
[] When two forces are equal in opposite directions, they are in a state of equilibrium
2: Friction
[] It can be hard to sometimes slide a paper across a table, roll a car across the ground, etc etc. This is because of a force called friction which resists motion
3: Displacement
[] Work is only "done" when the object or surroundings are having movement, or in motion, and this creates displacement
4: Force
[] A force is a push/pull in any direction, this is a simple definition so not much can be added.
5: Inertia
[] Inertia is a force that likes to remain unchanged, or without movement
6: Effort
[] "Meg is holding up weight without movement. She hasn't done any work since it did not move, but is tired. Why?" Effort! She still put in effort even though no "work" happened
7: Work
[] Force times displacement is the equation for work
8: Motion
[] Look back to #3, when there is motion we can tell work is done
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
Answer:
Greetings!
The correct answer is the last one, "When the future level of some variable is seen as a function other than time".
Explanation:
Along other forecasting methods, the moving average finds utility in cases when seasonality is a factor. This term refers to a set of variables unknown to (or uncontrolled by) the observer that influence the series model in some way.
By applying a moving average to a time series one can mitigate such irregular effects.
I hope this helps!
13.6/4^2 - (-13.6/3^2) = -13.6/16 + 13.6/9 = .66 eV<span>
</span>
Answer:
t = 17199 years
Explanation:
given,
mass of sample = 1.09 Kg
Activity of living material = 15 decays / min /g
Activity of living material = 15 x 1000 decays /min /kg
Activity of living material per 1.09 kg A = 1.09 x 15 x 1000 decays / min
Activity of after time t is A ' = 2020
half life = 57300 years
desegregation constant
λ = 0.693 / 5700
taking ln both side
t = 17199 years
Answer:
we don't know what school or class you go to so there's no way of knowing if we have the same one, your best bet is to ask question by question until you have all the answers
