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tino4ka555 [31]
3 years ago
10

You pull your little sister across a flat snowy field on a sled. Your sister plus the sled have a mass of 25 kg. The rope is at

an angle of 38 degrees to the ground. As you pull with a force of 29 N, the sled travels a distance of 52 m with a force of 30 N how much work do you do?
Physics
1 answer:
erik [133]3 years ago
7 0

Answer

Work done will be equal to 1229.296 J

Explanation:

We have given mass of the sister m = 25 kg

Angle between rope and ground \Theta =38^{\circ}

Force F = 30 N  

So horizontal force =Fcos\Theta =30\times cos38^{\circ}=23.64N

Distance traveled d = 52 m

'We have to find the wok done

Work done is equal to multiplication of horizontal force and distance

So work done W=23.64\times 52=1229.296J

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A wheel has a radius of 9 centimeters and an axle radius of 3 centimeters. The IMA of the system is ___?
otez555 [7]

Answer:

Answer is C.

Explanation:

To calculate the IMA for a wheel and axle, find the ratio of the larger radius to the smaller radius:

IMA = R/r

IMA = 9/3

IMA = 3

4 0
4 years ago
As an airplane is taking off at an airport its position is closely monitored by radar. The following three positions are measure
Sergeeva-Olga [200]

Answer: acceleration a = 25m/s^2

Explanation:

Given that:

The plane travels with constant acceleration

x1 = 241.22 m at t1 = 3.70 s

x2 = 297.60 m at t2 = 4.20 s

x3 = 360.23 m at t3 = 4.70 s.

We need to calculate the velocity in the two time intervals.

Interval 1:

Average Velocity v1 = ∆x/∆t = (x2 - x1)/(t2-t1)

v1 = (297.60-241.22)/(4.20-3.70) = 112.76m/s

Interval 2:

Average Velocity v2 = ∆x/∆t = (x3-x2)/(t3-t2)

v2 = (360.23-297.60)/(4.70-4.20)

v2 = 125.26m/s

Acceleration:

Acceleration a = ∆v/∆t

∆v = v2-v1 = 125.26m/s-112.76m/s = 12.5m/s

∆t = change in average time of the two intervals = (t3-t1)/2 = (4.70-3.70)/2 = 0.5s

a = 12.5/0.5 = 25m/s^2

4 0
3 years ago
Jenny wants to determine if a new brand name washing detergent is better than her old detergent she washed ten dirty t-shirts wi
katovenus [111]

Answer:


Independent variable: washer detergent

Dependent varaible: cleaing power of effectivenes of the detergent.


Explanation:


When an experiiment is performed there exists one independent variable, one dependent variable, and some other variables that must be controlled.


The goal of the experiment is to test a hypothesis, which is a statement that relates an effect with a cause and that must be proved true or false.


The effect in the dependent variable, and the cause is the independent variable.


Jenny (the scientist) wants to show how an effect or phenomenun, the dependent variable, is explained by the explanatory, independent, variable.


In the stated experiment, Jenny wants to know how the effectiveness of a new brand detergent and an old one compare with each other. Therefore, she designs a test in which she will determine how the brand of detergent may  explain (explanatory or independent variable) the cleaning power or effectiveness, the dependent variable.


Jenny only can manipulate the independent variable and observe the effect on the dependent variable.


To be conclusive, other variables must be controlled, like the fabric and the amount of dirt of the t-shirts.

4 0
4 years ago
A 6.00 kg object is lifted vertically through a distance of 5.25 m by a light string under a tension of 80.0 N. Find: (2 marks)
jeka57 [31]

Explanation:

It is given that,

Mas of the object, m = 6 kg

It is lifted through a distance, h = 5.25 m

Tension in the string, T = 80 N

(a) By considering the free body diagram of the object, the forces can be equated as :

T-mg=ma

a=\dfrac{T-mg}{m}

a=\dfrac{80-6\times 9.8}{6}

a=3.33\ m/s^2

Work done by tension, W_t=F\times h

W_t=80\times 5.25

W_t=420\ J

(b) Work done by gravity, W_g=mgh

W_g=6\times 9.8\times 5.25

W_g=308.7\ J

(c) Let v is the final speed of the object and u = 0

v=\sqrt{2ah}

v=\sqrt{2\times 3.33\times 5.25}

v = 5.91 m/s

Hence, this is the required solution.

7 0
4 years ago
12. A cross-country race car driver sets out on a 1.00 hour, 100.0 km race. At the halfway marker
Akimi4 [234]

Answer:

A.) Time = 0.625 hrs = 37.5 minutes

B.) Speed required = 133.33km/hr

Explanation:

Given the following :

Total race distance = 100km

Total time required = 1 hour = 60 minutes

Average speed after traveling 50km = 80km/hr

80km/hr : This means it will take one hour to cover a distance of 80km

Therefore, time taken to cove first 50km at that average speed equals :

1 hour = 80 km

t hours = 50km

80t = 50

t = 50/80

t = 5/8 hours

t = 0.625hours

t = 0.625 * 60 = 37.5minutes

B)

Average speed required to complete the race in 1 hour = 100km/hr

Time used to complete first 50km = 0.625 hour

Time remaining: (1 - 0.625) hour = 0.375

Speed required = Distance left / time left

Speed required = 50 / 0.375

Speed required = 133.33km/hr

8 0
3 years ago
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