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Digiron [165]
4 years ago
12

The driver of a car traveling at a speed of 25.5 m/s slams on the brakes and comes to a stop in 3.4 s. If we assume that the car

's speed changed at a constant rate (constant net force), find the following. What was the car's average speed during this 3.4 s interval? ______ m/s
How far did the car go in this 3.4 s interval? ____ m
Physics
1 answer:
marusya05 [52]4 years ago
5 0

Answer:

(a). The average speed of the car is 12.75 m/s

(b). The distance is 43.35 m.

Explanation:

Given that,

Initial speed = -25.5 m/s

Final speed = 0

Time = 3.4 s

(a). We need to calculate the average speed

Using formula of average speed

v_{avg}=\dfrac{v_{f}-v_{i}}{2}

Put the value into the formula

v_{avg}=\dfrac{0-(-25.5)}{2}

v_{avg}=12.75\ m/s

(b). We need to calculate the acceleration

Using equation of motion

v_{f}=v_{i}+at

a =\dfrac{v_{f}-v_{i}}{t}

a=\dfrac{-25.5-0}{3.4}

a=-7.5\ m/s^2

We need to calculate the distance

Using equation of motion

s = ut+\dfrac{1}{2}at^2

s=25.5\times3.4+\dfrac{1}{2}\times(-7.5)\times(3.4)^2

s=43.35\ m

Hence, (a). The average speed of the car is 12.75 m/s

(b). The distance is 43.35 m.

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Answer:

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Explanation:

Potential energy is stored in a state of readiness.

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Mathematically, potential energy is given by the formula;

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