<u>Answer: </u>
<em>Considering the II law of thermodynamics</em>
<em>From the figure</em>
<em>Out put of energy: </em>
Heat supplied from the source/ reservoir (Q₁) - Heat rejected to the surroundings from the system (Q) = Q₁ - Q₂. Also known as Net work done on the system.
<em>Input of energy: </em>
Amount of heat energy supplied to the system from the source (Q₁ ).
Efficiency (H.E) = η = Output÷ Input
η = (Q₁ - Q₂) ÷ Q₁
OR η = Wnet ÷ Q₁ ; since Wnet = (Q₁ - Q₂)
Answer:
a) 14.2 atm
b) 4.46 atm
c) 1.06 atm
Explanation:
For an ideal gas,
PV = nRT
P = pressure of the gas
V = volume occupied by the gas
n = number of moles of the gas
R = molar gas constant = 0.08206 L.atm/mol.K
T = temperature of the gas in Kelvin
a) For HF,
P =?, V = 2.5L, n = 1.35 moles, T = 320K
P = 1.35 × 0.08206 × 320/2.5
P = 14.2 atm
b) For NO₂
P =?, V = 4.75L, n = 0.86 moles, T = 300K
P = 0.86 × 0.08206 × 300/4.75
P = 4.46 atm
c) For CO₂
P =?, V = 5.5 × 10⁴ mL = 55L, n = 2.15 moles, T = 57°C = 330K
P = 2.15 × 0.08206 × 330/55
P = 1.06 atm
Answer:
C. Basic swimming capability.
Explanation:
one of the way before participating in any water-based sport is know how to do the basic swimming way.
Answer:
0 m/s^2
Explanation:
Acceleration is the change in velocity / time
=> In this case there isn't any change in velocity
=> It is = to 0.
