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3 years ago

Plz help me with this

Mathematics

2 answers:

saul85 [17]3 years ago

7 0

Your answer would be the second option, (-4,5).

We can find this by substituting in each point into the equation y < |x - 3| and seeing if it is true.

For the first one you get 1 < |2 - 1|. |2 - 1| = |-1| = 1, and 1 cannot be less than itself, so this is false.

For the second one you get 5 < |-4 - 3|. |-4 - 3| = |-7| = 7, and 5 is indeed less than 7, so this is correct.

I hope this helps!

Degger [83]3 years ago

4 0

Answer:

(0,3)

Step-by-step explanation:

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nikdorinn [45]

Answer:

R = 7,34 km

Ф = 63,43° north of east

Step-by-step explanation:

Let´s analyze each movement and find its perpendicular components. Then, we are going to add the components along the x and y axes to get the resultant and finally to calculate its magnitude and direction.

To determine the perpendicular components, we will use right triangles trigonometrics ratios.

Please see images for each displacement in attached file.

Displacement A: 2.50 km and 45° north of west

Ax= AcosФ = 2.50cos45° = 1.77 km (neg. direction)

Ay= AsenФ = 2.50sen45° = 1.77 km (pos. direction)

Displacement B: 4.70 km and 60° south of east

Bx= BcosФ = 4.70cos60° = 2,35 km (pos. direction)

By= BsenФ = 4.70sen60° = 4,07 km (neg. direction)

Displacement C: 1.30 km and 25° south of west

Cx= CcosФ = 1.30cos25° = 1,18 km (neg. direction)

Cy= CsenФ = 1.30sen25° = 0.55 km (neg. direction)

Displacement D: 5.10 km due east (0°)

Dx= DcosФ = 5.10 km (pos. direction)

Dy= DsenФ = 0 km

Displacement E: 1.70 km and 5° east of north

Ex= EsenФ = 1.70sen5° = 0,15 km (pos. direction)

Ey= EcosФ = 1.70cos5° = 1.69 km (pos. direction)

Displacement F: 7.20 km and 55° south of west

Fx= FcosФ = 7.20cos55° = 4.13 km (neg. direction)

Fy= FsenФ = 7.20sen55° = 5.90 km (neg. direction)

Displacement G: 2.80 km and 10° north of east

Gx= GcosФ = 2.80cos10° = 2.76 km (pos. direction)

Gy= GsenФ = 2.80sen10° = 0.49 km (pos. direction)

Now, we add the components along the x- and y- axis to find the components of the resultant (R):

Rx = Ax + Bx + Cx + Dx + Ex + Fx + Gx

Ry = Ay + By + Cy + Dy + Ey + Fy + Gy

Therefore,

Rx= (-1.77)+(2.35)+(-1.18)+(5.10)+(0.15)+(-4.13)+(2.76)

Ry= (1.77)+(-4.07)+(-0.55)+(0)+(1.69)+(-5.90)+(0.49)

Note: minus (-) symbol to negative directions

Rx = 3.28 km

Ry = - 6.57 km

Let´s use the Theorem of Pythagoras to find the magnitud ot the resultant:

$R = \sqrt{Rx^{2} +Ry^{2} }$

$R =\sqrt{(3.28)^{2}+(-6.57)^{2} }$

R = 7,34 km

To find the direction of the resultant:

tanФ = $\frac{Ry}{Rx}$

tanФ = $\frac{6.57}{3.28}$

tanФ = 2.00

Ф = tan-1 (2.00)

Ф = 63,43° north of east

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The given angle ( 47 degrees) and x are supplementary angles, which equal 180 degrees.

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At one company a level 1 engineer receives a salary of $45,000 and a level 2 receives a salary of $65,000. The company has a bud

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Answer:

Company will hire 3 Engineers of Level 1 and 10 Engineers of level 2.

Step-by-step explanation:

Let the number of engineers for level 1 be x.

Let the number of engineers for level 2 be y.

Given:

Total Number of engineers company can hire = 13

Now Total number of engineers are equal to sum of number of engineers for level 1 and number of engineers for level 2.

Hence Framing in the equation form we get;

$x+y=13 \ \ \ \ equation\ 1$

Also Given:

Salary of level 1 engineers = $45,000

Salary of level 2 engineers = $65,000

Total Budget of Company = $785,000

But Total Budget of Company depends upon the sum of Salary of level 1 engineers multiplied with number of level 1 engineers and Salary of level 2 engineers multiplied with number of level 2 engineers.

Hence equation can be framed as;

$45000x+65000y = 785000$