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3 years ago

Why is it possible to throw a 0.145 kg baseball much further than a 7 kg bowling ball

1 answer:

5 0

Simply because the baseball is much lighter than the bowling ball. Making it easier for the average adult to throw the baseball farther than the bowling ball

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How do I learn French fast for an examination

alexandr402 [8]

Explanation:

It isn't possible to learn an entire language fast. For an examination, memorise some of the easy words. Practice mew minutes speaking French and keep speaking it till you know it.

7 0

3 years ago

As the wave interacts with a wall, which kind of wave interaction is shown?

kramer

Reflection-----------------------------

3 0

3 years ago

Read 2 more answers

Ron weighs a bottle with a mass of 0.5 kilograms on a spring scale. The spring stretches by 1 centimeter. He then weighs a secon

Yuri [45]

Answer:

1 kg

Explanation:

Applying,

Hook's law,

F = ke................. Equation 1

Where F = force, k = force constant of the spring, e = extension.

But from the question,

The weight of the bottle is the force acting on the spring scale

therefore,

mg = ke............ Equation 2

Where m = mass of the bottle, g = acceleration due to gravity.

make k the subject of the equation

k = mg/e............ Equation 3

Given: m = 0.5 kg, e = 1 cm = 0.01 m

Constant: g = 9.8 m/s²

k = (0.5×9.8)/0.01

k = 490 N/m

If the mass of the second bottle is weighed,

given: e = 2 cm = 0.02 m

subtitute into equation 1

m×9.8 = 490×0.02

9.8m = 9.8

m = 9.8/9.8

m = 1 kg.

Hence the mass of the second bottle is 1 kg

5 0

3 years ago

A rope with a mass density of 1 kg/m has one end tied to a vertical support. You hold the other end so that the rope is horizont

PIT_PIT [208]

Answer:

$v' = 2.83 m/s$

Explanation:

Velocity of wave in stretched string is given by the formula

$v = \sqrt{\frac{T}{\mu}}$

here we know that

T = 4 N

also we know that linear mass density is given as

$\mu = 1 kg/m$

so we have

$v = \sqrt{\frac{4}{1}} = 2 m/s$

now the tension in the string is double

so the velocity is given as

$v' = \sqrt{\frac{8}{1}} = 2\sqrt2 m/s$

$v' = 2.83 m/s$

4 0

3 years ago

When viewing a piece of art that is behind glass, one often is affected by the light that is reflected off the front of the glas

Elza [17]

Answer:

t = 9.16 10⁻⁸ m

Explanation:

In this exercise we fear a case of interference by reflection,

We have two aspects

* when the light ray passes from the air to the TiO2 that has a higher refraction start, the reflected ray has a phase change of 180º

* when the beam is inside the material its wavelength changes

λₙ = λ₀ / n

with these two done the equation for destructive interference remains

2t = m λₙ

2nt = m λ₀

They ask us for the thickness t of the film for m = 1

t = m λ₀ / 2n

let's calculate

t = $\frac{1 \ 480 1 10^9 }{2 \ 2.62}$

t = 9.16 10⁻⁸ m

5 0

3 years ago